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Ivanshal [37]
2 years ago
15

Evaluate223×225Give your answer as a mixed number in its simplest form.

Mathematics
1 answer:
Feliz [49]2 years ago
5 0
The answer is 50, 175
You might be interested in
Is algebra.
Ket [755]

Answer:

6(x-10)(x+9)

Step-by-step explanation:

First, make A equal one by factoring out the greatest common factor, 6. This makes the new expression 6(x^{2} +x-90). Then, factor the remaining polynomial by finding two numbers that multiply to -90 and add to 1. These two numbers are -10 and 9. So, add each term to x and then multiply to get the final answer, 6(x-10)(x+9).

5 0
3 years ago
I will mark brainiest is my answer is right?
Dennis_Churaev [7]
Yes, that's correct.
3 0
3 years ago
Read 2 more answers
Can anyone answer this pls!!!!!!!!!!
gizmo_the_mogwai [7]

u₁₂ represents the amount of loan remaining after 12 years

<h3>How to interpret u₁₂?</h3>

The function is given as:

u₀ = 8000

u_n = u_{n-1}(1 + 0.054) - 500

Given that the subscript n in u_n represents number of years and u_n represents the amount left to be paid after n years.

We can conclude that:

u₁₂ represents the amount of loan remaining after 12 years

Read more about loan at
brainly.com/question/26011426

#SPJ1

6 0
2 years ago
Complete the following sentence with a power of ten greater than 1. A kilometer is times as large as a millimeter. Click on the
Gelneren [198K]

Answer:

A kilometer is 10⁶ times as large as a millimeter.

Step-by-step explanation:

In the metric system first we have: millimeter, centimeter, decimeter and meter. Each one of these is 10 times the other (1 centimeter is 10 millimeter, 1 decimeter is 10 centimeter, 1 meter is 10 decimeter). Therefore, 1 meter is 10x10x10 millimeter = 1 meter is 1000 millimeters.

But we know that 1 km is 1000 meters,

Therefore, 1 km = 1000 meter = 1, 000,000 milimeter = 10⁶ milimeter

So then, we have that 1 kilometer is 10⁶ as large as a milimeter.

3 0
3 years ago
Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


5 0
3 years ago
Read 2 more answers
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