Y = -2(x + 3)^2 - 4
First expand the parentheses:-
y = -2(x + 3)(x + 3) - 4
y = -2 [(x(x + 3) + 3(x + 3)] - 4
y = -2 ( x^2 + 3x + 3x + 9) - 4
y = -2(x^2 + 6x + 9) - 4
Now distribute the -2 over the parentheses:-
y = -2x^2 - 12x - 18 - 4
y = -2x^2 - 12x - 22 Answer
Answer:
31,41,51,71
Step-by-step explanation:
9/r= 3/10
Cross multiply:
3*r= 9*10
⇒ r= 9*10/3
⇒ r= 30
The final answer is 30~
An example of quadratic equation with this behavior is:

Which is sketched at the end of this answer.
A quadratic equation has the format:

It's roots are given by:

The number of roots depends on the discriminant
, that is:
- If
, it has two different real roots. - If
, it has one real root. - If
, it has no real roots.
In this problem, it will have only positive y-values if:
and 
Thus, an example is:

Which is sketched below.
A similar problem is given at brainly.com/question/19776811