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2 years ago

15

Simply the expression by combining like terms. 9x + 8 + 3x +4=

2 answers:

nikdorinn [45]2 years ago

7 0

9x + 3x = 12x
8 + 4 = 12
Final answer is 12x + 12

Effectus [21]2 years ago

3 0

The answer is 12x+12

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On Saturday moming, Owen earned $25. By the end of the aftemoon he had earned a total of $57. Enter an equation, using x as your

LekaFEV [45]

$58-$25=x this would be the equation i believe

5 0

2 years ago

A target with a diameter of 14cm has 4 scoring zones by concentric circles. The diameter of the center circle is 2 cm. The width

Leni [432]

Answer:

$48.98\%$

Step-by-step explanation:

we know that

The probability that it will hit a point in the outer (yellow) ring is equal to divide the area of the yellow ring by the total area of the target

step 1

Find the area of the yellow ring

$A=\pi [7^{2} -5^{2}]$

$A=24\pi\ cm^{2}$

step 2

Find the total area of the target

$A=\pi [7^{2}]$

$A=49\pi\ cm^{2}$

step 3

Find the probability

$24\pi/49\pi=0.4898$

Convert to percentage

$0.4898*100=48.98\%$

4 0

3 years ago

Read 2 more answers

The area of a polygon is the number of square units contained in its interior true or false

Vsevolod [243]

<span>False. Perimeter is a linear measure. Square units are for area.</span>

5 0

2 years ago

Find the intersection of the three sets: A = {–4, 3, 10}, B = {3, 6, 10, 15}, C = {–4, 10, 20}

Wittaler [7]

Answer:

10

Step-by-step explanation:

8 0

2 years ago

Plz need help on 1. 2. and 3 plz help and dont answer if you dont know it plz

sesenic [268]

Answer:

1) 32 $m^{6}$ $n^{14}$

2) 3 $j^{4}$ $k^{8}$

3) 135 $a^{11}$ $b^{16}$

Step-by-step explanation:

to know: when multiplying terms with same base and exponents, multiply the bases and add the exponents

to know: when dividing terms with same base and exponents, divide the bases and subtract the exponents

to know: whenever exponents are contained within a set of parentheses and separated by another set of parentheses, multiply the exponents

1) ( $4^{4}$ · $m^{12}$ · $n^{20}$ ) ÷ 2³ $m^{6}$ $n^{6}$ = 3 $j^{4}$ $k^{8}$

2) (15 $j^{5}$ $k^{2}$ · 25j² $k^{9}$ ) ÷ 5³j³k³ = (375 $j^{7}$ $k^{11}$ ) ÷ 125j³k³ = 3 $j^{4}$ $k^{8}$

3) (5 · 3³) $a^{11}$ $b^{16}$ = 135 $a^{11}$ $b^{16}$

5 0

2 years ago