The factory made 7 batches of granola bars yesterday.
Answer:
I'm pretty sure it's 5 hours tutoring and 7 hours landscaping.
Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:
In which a is the probability that a customer saw the advertisement on the internet but not on television and is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:
12% saw it on both the internet and on television.
This means that
20% saw it on television
This means that
37% of customers saw the advertisement on the internet
This means that
What is the probability that a randomly selected customer saw the advertisement on the internet or on television
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Answer:
A = 25.758 m²
Step-by-step explanation:
Width of the sand pit, b = 2.7 m
Length of the sand pit, l = 9.54 m
We want to cover the sand pit with a piece of plastic. We need to find how many square meters of plastic will be needed to cover the sand pit. It is equal to the area of sand pit. It is in the shape of rectangle. Its area is given by :
A = l × b
A = 2.7 × 9.54
A = 25.758 m²
So, 25.758 m² of plastic will be needed to cover the sand pit.
Answer:
area of rectangle =length ×width
area of rectangle=12yd×15yd
area of rectangle=180yd²