Answer:
u lookn hot tonight baby
Step-by-step explanation:
<h3>
Answer: Choice B</h3><h3>
sqrt(3)/2, 1/2, sqrt(3)</h3>
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Explanation:
Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12
Sin(angle) = opposite/hypotenuse
sin(A) = BC/AB
sin(A) = 6sqrt(3)/12
sin(A) = sqrt(3)/2
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Cosine is the ratio of the adjacent and hypotenuse
cos(angle) = adjacent/hypotenuse
cos(A) = AC/AB
cos(A) = 6/12
cos(A) = 1/2
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Tangent is the ratio of the opposite and adjacent
tan(angle) = opposite/adjacent
tan(A) = BC/AC
tan(A) = 6sqrt(3)/6
tan(A) = sqrt(3)
The given expression is:

So, there are two terms in the expression
1)

2) -5
The constant term is -5.
The co-efficient of

is 4.
Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

In which




So

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.