Question

Guys help me pls I need it immediately

Answer 1

Answer:

Hey there!

First, we want to find the side length of the large triangle.

1/2bh=y cm^2

bh=2y cm^2

Since b and h are the same here, we have b^2= 2y, $b=\sqrt{2y}$.

And we have FC=$\frac{\sqrt{2y} }{2}$.

Area of shaded triangle: $\frac{1}{2} (\frac{\sqrt{2y} }{2})(\frac{\sqrt{2y} }{2})$.

This is equal to: $\frac{1}{2}(\frac{2y}{4})$, or y/4.

Let me know if this helps :)