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2 years ago

Distribute -6 ( 3c + 5)

Mathematics

1 answer:

Marina86 [1]2 years ago

5 0

Step-by-step explanation:

-6( 3c + 5)

Distributing

= - 18c - 30

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Write the equation of a line perpendicular to y=3x+1and goes through the point ( 6,2) y=−13x+4 y=−13x−4 y=3x+4 y=3x−4

Korolek [52]

Answer:

$y=-\frac{1}{3}x+4$

Step-by-step explanation:

step 1

Find the slope of the perpendicular line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal

(the product of their slopes is equal to -1)

In this problem

we have

$y=3x+1$

The equation of the given line is $m=3$

the slope of the perpendicular line to the given line is

$m=-\frac{1}{3}$

step 2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{1}{3}$

$(x1,y1)=(6,2)$

substitute

$y-2=-\frac{1}{3}(x-6)$

Convert to slope intercept form

$y=mx+b$

Distribute right side

$y-2=-\frac{1}{3}x+2$

$y=-\frac{1}{3}x+2+2$

$y=-\frac{1}{3}x+4$

6 0

3 years ago

Find the slope. ( include whether positive or negative.)

dsp73

Answer:

that is a negative slope

but dont know how to find the slope sorry

Step-by-step explanation:

3 0

3 years ago

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Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

3 0

1 year ago

What kind of reasoning is kim using? kim notices that 24 = 6 + 18, 63 = 9 + 54, 39 = 12 + 27, and 72 = 9 + 63, so she thinks it

SVETLANKA909090 [29]

Reasonings are divided into three categories: (1) inductive, (2) deductive, and (3) causal reasoning. The type of reasoning that is depicted in the given above is inductive reasoning. This is because Kim was able to derive to a conclusion by citation of different examples. Among the three categories, inductive reasoning is the most commonly used.

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3 years ago

Which point is located in Quadrant 12 A point P B point o C point OD points

netineya [11]

C point i think tht rught

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2 years ago

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