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1 year ago

A flag pole is casting a 20ft. shadow. The flag pole measures 16 ft. Find the Angle of elevation of the sun.

Mathematics

2 answers:

Mamont248 [21]1 year ago

7 0

Answer:

53 the correct answer off your question.

oksano4ka [1.4K]1 year ago

4 0

Let's see

tanØ=16/20
tanØ=4/5
tanØ=0.8
Ø=53°

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HELP ME WITH MATH PLZZ

Andrew [12]

Answer:

d.exponential because as x increases by 1 y is multiplied by 3

Step-by-step explanation:

hope it help

6 0

3 years ago

A technical machinist is asked to build a cubical steel tank that will hold of water. Calculate in meters the smallest possible

Charra [1.4K]

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

$Volume = 565L$

Required

The smallest length of the tank

Since the tank is cubical, then the volume is:

$Volume = Length^3$

This gives:

$565L= Length^3$

Express as $m^3$

$\frac{565m^3}{1000} = Length^3$

$0.565m^3 = Length^3$

Take cube roots of both sides

$0.8267m = Length$

Rewrite as:

$Length = 0.8267m$

Approximate

$Length = 0.83m$

5 0

2 years ago

As voters exit the polls, you ask a representative random sample of voters if they voted for a proposition. If the true percenta

tresset_1 [31]

Answer:

The probability is 0.057797

Step-by-step explanation:

Consider the provided information.

It is given that true percentage of voters who vote for the proposition is 63%,

Let p is probability of success.

According to the binomial distribution:

$P(x;p,n)=^nC_x(p)^x(1-p)^{(n-x)}$

Substitute n=7, p=0.63 and x=2 in the above formula.

$P(x;p,n)=^7C_2(0.63)^2(1-0.63)^{(7-2)}$

$P(x;p,n)=\frac{7!}{2!5!}(0.3969)(0.37)^{5}\\P(x;p,n)=21(0.3969)(0.37)^{5}\\P(x;p,n)=0.0577974947199\\P(x;p,n)\approx0.057797$

Hence, the probability is 0.057797

8 0

3 years ago

Write absolute value of the following rational number -6/11 , 15/21 , -9 , -21/-37 , 31/-54

Dahasolnce [82]

Answer:

6/11, 15/21, 9, 27/37, 31/54

Step-by-step explanation:

Absolute value is when you determine the distance between a value and zero . Since you will always have a positive distance, your absolute values are positive as well.

4 0

3 years ago

Which polynomial correctly combines the like terms and puts the given polynomial in standard form? -5x^3y^3+8x^4y^2-xy^5-2x^2y^4

victus00 [196]

Given:

The polynomial is:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

To find:

The simplified form of the given polynomial in standard form.

Solution:

We have,

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

Combining the like terms, we get

$=-5x^3y^3+8x^4y^2+(-2x^2y^4+3x^2y^4)+8x^6+(-xy^5-6xy^5)$

$=-5x^3y^3+8x^4y^2+x^2y^4+8x^6-7xy^5$

Now, rewrite this polynomial in standard form.

$=8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$

Therefore, the required polynomial in standard form is $8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$ .

8 0

2 years ago