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Anna11 [10]
3 years ago
8

PLZ CLICK!! Need help ASAP! I have a time limit.

Mathematics
2 answers:
babymother [125]3 years ago
7 0

Answer:

what's the question for this?

algol [13]3 years ago
5 0

Answer:

33

Step-by-step explanation:

so this is perimeter and area

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Beth has 250 comic books in her collection. She begins to sell 20 of them each week. Martin has 80 comic books in his collection
guapka [62]

Answer:

250 - 20 < 80 + 15x

Step-by-step explanation:

Given that

Beth has 250 books and 20 books sold each week

While on the other hand, Martin has 80 books and sell 15 books each week

Let us assume each week be x

Now the equations are  

Beth         250 - 20x            

Martin       80 + 15 x

Now the inequality would be

250 - 20 < 80 + 15x

8 0
3 years ago
How can you tell that a fraction is a unit fraction
a_sh-v [17]
You can tell that a fraction is a unit fraction when it is over a unit of one. This is also known as unit rate.
6 0
3 years ago
Read 2 more answers
How do you write 145,934 in scientific notation
Gre4nikov [31]

Answer:

1.45934 × 10^5

Step-by-step explanation:

3 0
3 years ago
If x-y=5 then how does y=-2x-4
mixer [17]
Based on my knowledge, you’d set both equations equal to y, and then set both sides equal to each other then solve.

y=-5+x
y=-2x-4
-5+x=-2x-4
then solve from there

(this could be completely wrong, so don’t only go by my opinion)
3 0
4 years ago
What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
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