This as a decimal 6th

Can the polynomial below be factored into a perfect square? If not, select the answer that best describes why not.

pickupchik [31]

Answer:

C. It cannot be factored into a perfect square.

Step-by-step explanation:

Take the square roots of all the numbers present (64, 49, 8) and you will find that 8, the constant, is not a perfect square.

8 0

3 years ago

Solve<br><br> 4(3x - 2) = 52

guapka [62]

Answer:

x= 5

Step-by-step explanation:

first we open brackets

12x-8=52

then transpose

12x= 52+8

12x= 60

x= 60/12

x= 5

hope it helps , pls mark me as brainliest

5 0

4 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$

Volume of the box at x= 1.59:

$V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\$

Volume of the box at x= 0.53:

$V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3$

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0

3 years ago

Line ef is tangent to circle g at point h. segment gh is a radius of circle g. what can be concluded about triangle fhg?

solong [7]

We know that

A line tangent to a circle is perpendicular to the radius to the point of tangency.
so
<span>Line ef is </span>perpendicular to the segment gh

hence
Triangle FHG is a right triangle

3 0

3 years ago

Read 2 more answers

Which of the following equations has the given solution set?

tester [92]

-2m + 5 = 2m + 5
2m + 2m = 5 - 5
4m = 0
m = 0

-2m + 5 = -2m + 5
-2m + 2m = 5 - 5
0 = 0

-2m + 5 = -2m - 5
-2m + 2m = 5 + 5
0 = 10
Solution set is Ф
The third equation is the correct answer.

8 0

3 years ago

This as a decimal 6th​

This as a decimal 6th