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kumpel [21]
2 years ago
14

This as a decimal 6th​

Mathematics
1 answer:
makkiz [27]2 years ago
8 0

Answer:

the answer to the question is 3.2

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Find the area of the region bounded by the line y=3x-6 and line y=-2x+8.
Vikentia [17]

Answer:

A = 12/5 units

Step-by-step explanation:

USING ALGEBRA:

We can find the intersection point between these two lines;

y = 3x - 6

y = -2x + 8

Set these two equations equal to each other.

3x - 6 = -2x + 8

Add 2x to both sides of the equation.

5x - 6 = 8

Add 6 to both sides of the equation.

5x = 14

Divide both sides of the equation by 5.

x = 14/5  

Find the y-value where these points intersect by plugging this x-value back into either equation.

y = 3(14/5) - 6

Multiply and simplify.

y = 42/5 - 6

Multiply 6 by (5/5) to get common denominators.

y = 42/5 - 30/5  

Subtract and simplify.

y = 12/5

These two lines intersect at the point 12/5. This is the height of the triangle formed by these two lines and the x-axis.

Now let's find the roots of these equations (where they touch the x-axis) so we can determine the base of the triangle.

Set both equations equal to 0.

(I) 0 = 3x - 6  

Add 6 both sides of the equation.

6 = 3x

Divide both sides of the equation by 3.

x = 2  

Set the second equation equal to 0.

(II) 0 = -2x + 8

Add 2x to both sides of the equation.

2x = 8

Divide both sides of the equation by 2.

x = 4

The base of the triangle is from (2,0) to (4,0), making it a length of 2 units.

The height of the triangle is 12/5 units.

Formula for the Area of a Triangle:

A = 1/2bh

Substitute 2 for b and 14/5 for h.

A = (1/2) · (2) · (12/5)

Multiply and simplify.

A = 12/5

The area of the region bounded by the lines y = 3x - 6 and y = -2x + 8 between the x-axis is 12/5 units.

3 0
2 years ago
Anonymous 3 years ago
amm1812
Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.

Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.

From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH

Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees

Recall that mHFG + mACB = 90 degrees

Thus, mHFG + mACB = mHFG + mDFH

Therefore, mACB = mDFH.
5 0
3 years ago
If f(x)= -3x-5 and g(x)= 4x-2 find (f+g)(x)
juin [17]

Known :

f(x) = -3x - 5

g(x) = 4x - 2

Asked :

(f+g)(x) = ...?

Answer :

(f+g)(x) = (-3x - 5) + (4x - 2)

= (-3x + 4x) + (-5 - 2)

= x + (-7)

= <u>x </u><u>-</u><u> </u><u>7</u>

So, the value of (f+g)(x) is x - 7

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

5 0
3 years ago
Read 2 more answers
X+4y=4 y in terms of x
Alinara [238K]

Answer:

x + 4y = 4

4y = 4 - x

multiply both sides by 1/4

y = 1/4( 4- x)

y = 1- 1/4x

3 0
2 years ago
Read 2 more answers
 (6,-3) and y = - 6x - 3
Hatshy [7]
Wait what's the question tho?
is it if this point is on the line?
cause it's not
-y=mx+b
3=-6(6)-3
-3=-36-3
-3 does not equal -39
hence, point is not on the line
3 0
3 years ago
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