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Yanka [14]
3 years ago
10

The first two angles in a triangle are 100 degrees and 50 degrees. What does the third angle have to be?

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0
The answer is C: 30 degrees
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3 years ago
In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?
vaieri [72.5K]

Answer:

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And  Cos B = \frac{CB}{AB}.

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

                               Hypotenuse = AB\\Base = CB\\Perpendicular = AC

So,                            Sin\theta = \frac{perpendicular}{hypotenuse}

                                SinB = \frac{AC}{AB}

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

                               SinA= \frac{CB}{AB}

Again,                    Cos\theta= \frac{base}{hypotenuse}

Then,                    CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

Hence,

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

                               

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Top: 6, 9, and 13

Bottom: 11 and you got the rest right

Step-by-step explanation:

This is easy

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