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marshall27 [118]
3 years ago
7

60 points

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0

Answer:

2 is C. , 3 is C. , 4 is D.  

Step-by-step explanation:

2

Square roots are not polynomials

3

The highest degree of one term in the polynomial is 4

4

Terms are separated by (+) or (-) signs. If you count them up there are 4

ra1l [238]3 years ago
3 0

Answer:

C, D, D, B

Step-by-step explanation:

2. A polynomial has only integer exponents, no square roots.  So C is not a polynomial.

3. The degree of the polynomial is the sum of the exponents of the highest term.  p has an exponent of 1 and q has an exponent 4, so 1+4 = 5. D

4. Count the number of terms being added or subtracted.  p^3, 4pq^2, q^2, and -3q.  So there are 4 terms. D

5. Standard form of a polynomial is written from the highest exponent to the lowest.  So the answer is B.

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a blue number cube and a green number cube are rolled.Both number cubes have the number 1 through 6 on them. What is the probabi
Alenkinab [10]

Answer:

We are assuming the numbers 1 - 6 on the cubes?

If so,

Blue (3, 4, 5, or 6) is 4/6 or 2/3 chance

Green(1,3,5) is 3/6 or 1/2 chance

To get both the P is 2/3 times 1/2

Step-by-step explanation:

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3 years ago
Find the value of x. What is the value of x?
Gre4nikov [31]

Answer:

x = 16

Step-by-step explanation:

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This essentially means the following equation can be formed;

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Inverse operations,

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6 0
3 years ago
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marin [14]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
Enter the number of complex zeros for the polynomial function in the box. f(x)=x3−96x2+400
ioda

Solution:

There is no (zero) complex zeros for the given polynomial.

Explanation:

We apply Descartes' rule of sign to identify the number of complex roots.

The given polynomial is f(x)=x^3-96x^2+400

Let us see the number of sign changes in f(x)

+,-,+

There are 2 sign changes in f(x). One from plus to minus and second from plus to minus. Hence, there 2 or 0 positive roots.

Now, let us see the number of sign changes in f(-x)

f(-x)=-x^3-96x^2+400

-,-,+

There are only one sign change. Hence, there will be 1 negative roots.

The degree of the polynomial is 3. Hence, there will be exactly 3 zeros.

Therefore, the possible numbers of zeros are

2 positive, 1 negative and 0 complex

0 positive, 1 negative and 2 complex.

Hence, possible number of complex zeros are 0 and 2.

Now, we graph the function in xy plane and see that the graph cuts the x axis at three points. It means all the zeros are real , which is the case of first possibility (2 positive, 1 negative and 0 complex).

Hence, the number of complex zeros for the given polynomial is zero.

5 0
3 years ago
Read 2 more answers
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