All categories

3 years ago

The tables represent the functions f(x) and g(x).

Mathematics

1 answer:

adell [148]3 years ago

4 0

Answer:

Step-by-step explanation:

it's - 6 Anasta :)

You might be interested in

Ryan got $25 for his birthday. His dad told him not to spend it all in one place, so he wants to divide it up evenly between 5 c

vodka [1.7K]

Answer:

Step-by-step explanation:

When you divide 25/5 the answer is 5 dollars per store

7 0

3 years ago

Read 2 more answers

Omar deposited $4000 into an account with 4.4% interest, compounded quarterly. Assuming that no withdrawals are made, how much w

melamori03 [73]

The formula you want is: fv=p(1+int/c)^(nc)
future value
principal
int
compound
years

7 0

2 years ago

a club put its members into 5 groups for an activity. After 7 student have to leave early, there are only 3 students left to fin

Zanzabum

Answer:

2 students in each group

Step-by-step explanation:

If there were 5 groups and after a while 7 students leave early and 3 students remain to do the activity, if you add 7 + 3 = 10 divide it by 5, the number of groups in the activity, you would get 2 students in each group.

6 0

3 years ago

Read 2 more answers

Can someone pls answer this question what is 12 +z=15

ANTONII [103]

12 + z = 15

12 - 12 + z = 15 - 12

0 + z = 3

z = 3

3 0

3 years ago

Read 2 more answers

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

3 years ago