1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
miss Akunina [59]
3 years ago
14

What is the mode of 7 3 3 6 3 7

Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0

Answer:

3

Step-by-step explanation:

Since 3 occurs the most in the set of data, it is the mode.

<u>Mode:</u> The mode is the value that appears most frequently in a data set.

I hope this helps! Have a great day! :)

Amiraneli [1.4K]3 years ago
4 0

Answer:

3

Step-by-step explanation:

3,3,3,6,7,7

the mode is the number the occurs the most and 3 is there 3 times so it is the mode

You might be interested in
Which of the functions have a range of all real numbers? Check all that apply.
Svetach [21]

Answer:

B. y = tan x  and  C. y = cot x

Step-by-step explanation:

Range:

range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.

Given:

From the given options

the range of tanx and cotx are all real numbers

as the period of tanx and cotx are π

where as range of secx is all real numbers except π/2 + n*π i.e.

(-∞ , -1] U [1 , + ∞)

And range of cscx is all real numbers except n*π i.e.

(-∞ , -1] U [1 , + ∞)

So from the given option:

option B and C are correct while A and D are not !

6 0
3 years ago
Read 2 more answers
HELPPPP PLEASE!!!! Don't understand
iragen [17]

Answer: 20% is your answer


Step-by-step explanation:

180-150=30

30 divided by 150 = .2 which is 20%

7 0
3 years ago
Read 2 more answers
100*.005<br><img src="https://tex.z-dn.net/?f=100%20%5Ctimes%20.005" id="TexFormula1" title="100 \times .005" alt="100 \times .0
andrew11 [14]
Answer is .5
move decimal place 2 places right
7 0
3 years ago
Mario has a business selling muffins. Let x be the price of a muffin. Then, the profit P for Mario’s business is given by p(x)=-
Rufina [12.5K]
To make a positive profit p(x)>0 we need to make:
-100 x^{2} +350x-150 \ \textgreater \  0

Now we solve this for x:
-2 x^{2} +7x-3 \ \textgreater \ 0

We have:
a = -2
b = 7
c = -3

We will use formula for quadratic equation:
x_{1} =  \frac{-b+ \sqrt{ b^{2}-4ac } }{2a}  \\  \\  x_{2} =  \frac{-b- \sqrt{ b^{2}-4ac } }{2a}  \\  \\  x_{1} =  \frac{-7+ \sqrt{ 49-24 } }{-4} = \frac{-7+5 }{-4} = \frac{-2 }{-4} = \frac{1}{2}  \\  \\  x_{2} =  \frac{-7- \sqrt{ 49-24 } }{-4}  = \frac{-7-5 }{-4} = \frac{-12 }{-4} = 3

We got two solutions. One is fraction other is whole number. We will not consider fraction because the amount of muffins sold must be whole number. So our solution is:
x>3
5 0
3 years ago
Read 2 more answers
I will mark you brainliest if your answer is right
rusak2 [61]
12.72 is the answer
8 0
3 years ago
Other questions:
  • 1/4 + 1/8 + 1/8 - how do u make this equal 3/4 ​
    7·1 answer
  • When adding 32.6 to a certain number, the sum is 36.14, as seen below. What number should go in the box to complete the addition
    6·2 answers
  • In an elementary school classroom, two students are given the task of cleaning the chalkboard. The first student can clean it by
    8·2 answers
  • Need help on the answer
    11·2 answers
  • 7:
    15·2 answers
  • The equation of a circle is ​ (x−2)^2+(y−16)^2=169 ​ . What is the circle's radius?
    10·1 answer
  • What is the range of the below relation? {(3,-1), (-1,-4), (-4,6), (6,-1)}
    5·1 answer
  • Explain how to create a graph to model the relationship between the 2 quantities in the table. A 2-column table with 4 rows. Col
    10·1 answer
  • What is the range of the cluster in the scatter plot? Between 5 m and 7 m Between 1 m and 6 m Between 1 s and 9 s Between 1 s an
    10·1 answer
  • Let f(x)=12x^5-36x^4-6x^3 and g(x)=6x^2. Find f(x) over g(x)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!