Answer:
y=15
x=43
(any variable can be used, I used x and y to make it easier to show)
Step-by-step explanation:
x+y=58
x-y=28
get x by its self
x=58-y
then subsitute into the other equation
(58-y)-y=28
58-2y=28
-2y=-30
y=15
sub. again
x+15=58
x=43
Answer:
Domain → 0 < x < 5
Step-by-step explanation:
Sasha sells T-shirts and earns a fixed amount plus a commission by selling each shirt. (As given in the table)
Table attached shows a linear function (A regular increase in total pay with the increase in number of shirts sold)
So the input values of the table (Number of shirts sold) will represent the domain of the linear function.
Hence, reasonable domain for the function will be → 0 < x < 5
Answer:
The percentage of workers not wearing the helmets is 5.3 %.
Step-by-step explanation:
A safety committee randomly examined 900 construction workers during their work, and found that 48 workers were not wearing helmets. Estimate the percentage of workers who do not wear protective masks during their working time with 98% confidence
total workers = 900
Not wearing helmet = 48
Percentage which are not wearing the helmets
=
%
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
Answer:
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Step-by-step explanation:
Given that :
Mean = 265
standard deviation = 14
The formula for calculating the z score is 
x = μ + σz
At middle of 50% i.e 0.50
The critical value for 
From standard normal table
+ 0.67 or -0.67
So; when z = -0.67
x = μ + σz
x = 265 + 14(-0.67)
x = 265 -9.38
x = 255.62
when z = +0.67
x = μ + σz
x = 265 + 14 (0.67)
x = 265 + 9.38
x = 274.38
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days