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pychu [463]
4 years ago
7

5x+4y= 10 –5x+y = 15

Mathematics
1 answer:
Ivahew [28]4 years ago
6 0

Answer:

what exactly are we trying to solve for

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What is the common number of 5,4,100,1
cestrela7 [59]

Answer:

1

Step-by-step explanation:

These number can be de composed in primer factors as it is shown:

100=5*5*2*2*1

5=5*1

4=2*2*1

1=1

Where we can see that the only common number is 1

6 0
3 years ago
If the y is infinity and f(n/y)*1/y is 1/(x^2 + x), what is f(x)?
erastova [34]

Answer:

x"2^^1/y

I took this test and got question 4 correct

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4 0
2 years ago
Just to cover your
Makovka662 [10]

Answer:

It is 25$

Step-by-step explanation:

lol, it should be obvious. -_-

6 0
4 years ago
Read 2 more answers
Due this Thursday.. help pls.​
ra1l [238]

9514 1404 393

Answer:

  9.90×10^-15

Step-by-step explanation:

The leading non-zero digit must be move 15 places to the left to put it in the units place. Having done that, its original value will be restored by multiplying by 10^-15.

Rounded to 3 significant figures, 989912345 becomes 990. The trailing zero must be kept as part of the number to indicate that there are 3 significant figures.

In scientific notation, the number is ...

  9.90×10^-15

_____

<em>Additional comment</em>

If the number can be copied and pasted to a spreadsheet, it can be formatted to scientific notation with the required number of digits. Here, we can't copy the number from the image, so we have marked off the decimal places in a way that makes them easier to count. Copying the given number text would avoid any transcription errors.

8 0
3 years ago
Which side will require the use of the distance formula to find the length?
Bad White [126]

Answer:

CD

Step-by-step explanation:

For all sides except CD, you do not need the distance formula, since they are vertical or horizontal, meaning that you can find their length simply through subtraction. However, with side CD, since it is diagonal, you need to form a right triangle with to solve its length. Hope this helps!

4 0
3 years ago
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