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olya-2409 [2.1K]
3 years ago
15

Average score in the first 7 tests is 82. How much do you need to score to get an average of 85?

Mathematics
1 answer:
RSB [31]3 years ago
5 0

X+X+X+X+X+X+X/7=82

X+X+X+X+X+X+X+X/8=85

X+X+X+X+X+X+X=574

X+X+X+X+X+X+X+X=680

X=106

You need to score 106

Hope this helps :D

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4 years ago
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sineoko [7]

Answer:

2 x 2 x 7, or 2^2 x 7

Step-by-step explanation:

Let us use prime factorization to find the prime numbers that make up 28:

28 = 2 x 14            

2 is a prime number, 14 is not, so we have our first prime, 2.

14 = 2 x 7      

We then further break the number down into two prime numbers, 2 and 7. Since 2 and 7 are prime and we can't break them down any further our answer is 2 x 2 x 7, or 2^2 x 7.

3 0
4 years ago
Please help! will give brainliest !!
Veseljchak [2.6K]

Answer:

1, 2, 8, 128, 32768

Step-by-step explanation:

recursive \: formula: \\  a _{n} = 2. {( a_{n - 1} )}^{2}  \\  \\ a _{1} = 1...(given) \\  \\ a _{2} = 2. {( a_{2 - 1} )}^{2}   = 2 {(a _{1} )}^{2}  = 2 {(1)}^{2}  \\  \\  a _{2} = 2\\  \\a _{3} = 2. {( a_{3 - 1} )}^{2}   = 2 {(a _{2} )}^{2}  = 2 {(2)}^{2}  \\  \\  a _{3} = 8\\  \\a _{4} = 2. {( a_{4 - 1} )}^{2}   = 2 {(a _{3} )}^{2}  = 2 {(8)}^{2}  \\  \\  a _{4} = 128\\  \\a _{5} = 2. {( a_{5 - 1} )}^{2}   = 2 {(a _{4} )}^{2}  = 2 {(128)}^{2}  \\  \\  a _{5} = 32,768\\  \\

Thus the first five terms are: 1, 2, 8, 128, 32768.

5 0
3 years ago
Given Q is between J and K, JQ is five times the length of JK and JK=42 find the length of JQ
Alex73 [517]

Answer:

210

Step-by-step explanation:

JQ is 5 times the length of JK

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● JQ = 210

8 0
3 years ago
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Irina18 [472]
Yochanan walked 5 miles.

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If he walked for 1 hour at a speed of 5 miles per hour, then he walked for 5 miles.
5 0
4 years ago
Read 2 more answers
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