<img src="https://tex.z-dn.net/?f=%5Cfrac%7B-2x%5E%7B2%7D%20%7D%7B-4x%5E%7B2%7D%20%7D" id="TexFormula1" title="\frac{-2x^{2} }{-

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zimovet [89]

3 years ago

4x^{2} }" alt="\frac{-2x^{2} }{-4x^{2} }" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

kakasveta [241]3 years ago

7 0

Are you looking to simplify it? If so I think the answer would be 1/2.

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Given that (8,-1) is on the graph of f(x), find

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Answer:

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Step-by-step explanation:

(8, -1) => (-2/3x, f(-2/3x))

therefore

-2/3x = 8

x = 8 *-3/2

x = -12

f(-2/3x) = -1

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(-12,-1)

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Answer:

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Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

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2 years ago