hii!
n(n-4) = 60
n^2 - 4n - 60 = 0
( n - 10 )(n + 6 ) = 0
n-10 = 0 ---> n = 10 ---> 10*(10-4) = 10*6 = 60
n+6 = 0 --> n = -6 ---> -6 * (-6-4) = -6 * -10 = 60
Answer:
I think it is the last one
Step-by-step explanatio
Answer:
8 * (7 + 4)
See process below
Step-by-step explanation:
We start by writing each number in PRIME factor form:
56 = 2 * 2 * 2 * 7
32 = 2 * 2 * 2 * 2 * 2
Notice that the factors that are common to BOTH numbers are 2 * 2 * 2 (the product of three factors of 2).Therefore we see that the greatest common factor for the given numbers is : 2 * 2 * 2 = 8
Using this, we can write the two numbers as the product of this common factor (8) times the factors that are left on each:
56 = 8 * 7
32 = 8 * 2 * 2 = 8 * 4
We can then use distributive property to "extract" that common factor (8) from the given addition as shown below:
56 + 32
8 * 7 + 8 * 4
8 * (7 + 4)
8 * (11)
88
Step-by-step explanation:
what was his starting balance ?
