CAN SOMEONE PLEASE HELP MEEEE!!!!
1 answer:
<u>Question</u><u>:</u>
In triangle JKL, the measure of angle L = 90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of angle J?
__________________________________________________
<u>Solution</u><u>:</u>
The triangle JKL should look like that in the attachment.
Cosine of J = adjacent side/hypotenuse
= LJ/KJ
= 35/37
You might be interested in
Answer:
Step-by-step explanation:
Step1: find the interval of roots. Consider -3 and -2
Hence, the root must be on [-3,-2]
Step2: consider the middle point -2.5
Then, the root must be on [-3, -2.5]
Step 3: Repeat step 2 by finding the value of f at the middle point -2.75
Step 3: Repeat step 2 by finding the value of f at the middle point of the interval [-2.75,-2.5] which is -2.625
Step4: Repeat step 2 on [-2.75, -2.625]
Repeat step 2 until you got the root which is -2.701
Answer:
slope of EF=
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
∠SUT=21°
Step-by-step explanation:
two line are perpendicular to each other if product of their slope equal to -1
=-1
slope of HE==-
slope of EF=
slope of EF=-1=
slope of EF= answer
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
given ∠SUT=3x+6
∠RUS=5x-4
∠SUT=∠RUS
3x+6=5x-4
x=5
∠SUT=3x+6=15+6=21°
∠SUT=21°