All categories

3 years ago

CAN SOMEONE PLEASE HELP MEEEE!!!!

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

<u>Question</u><u>:</u>

In triangle JKL, the measure of angle L = 90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of angle J?

__________________________________________________

<u>Solution</u><u>:</u>

The triangle JKL should look like that in the attachment.

Cosine of J = adjacent side/hypotenuse

= LJ/KJ

= 35/37

You might be interested in

PLEASE ASAP FOR FULL POINTS

NARA [144]

It’s between B or C
Sorry if I’m wrong

3 0

3 years ago

April 15 is the _____. date you will receive your tax refund date you will receive your W-2 form deadline to file your tax retur

Jet001 [13]

I think that date has been changed...but it used to be the deadline to file ur taxes

4 0

3 years ago

Read 2 more answers

Find an equation of the plane with x-intercept a, y-intercept b, and z-intercept c. What is the distance between the origin and

Elenna [48]

Answer:

The equation is:

(1/a)x + (1/b)y + (1/c)z = 1

Step-by-step explanation:

The direction vector between the points (a, 0, 0) and (0, b, 0) is given as:

<0 - a, b - 0, 0 - 0>

<-a, b, 0> .....................(1)

The direction vector between (0, 0, c) and (0, b, 0) is given as:

<0 - 0, b - 0, 0 - c>

= <0, b, -c> .....................(2)

To obtain the direction vector that is normal to the surface of the plane, we take the cross product of (1) and (2).

Doing this, we have:

<-a, b, 0> × <0, b, -c> = <-bc, -ac, -ab>

To find the scalar equation of the plane we can use any of the points that we know. Using (0, b, 0), we have:

(-bc)x + (-ac)y + (-ab)z = (-bc)0 + (-ac)b + (-ab)0

(bc)x + (ac)y + (ab)z = (ac)b

Dividing both sides by abc, we have:

(1/a)x + (1/b)y + (1/c)z = 1

3 0

3 years ago

What is the slope of 2x+3y=15

Fynjy0 [20]

Note that the slope-intercept form is: y = mx + b

First, set the equation as such

2x (-2x) + 3y = (- 2x) + 15

3y = -2x + 15

Isolate the y. Divide 3 from both sides

(3y)/3 = (-2x + 15)/3

y = (-2/3)x + 5

-2/3 is your slope

hope this helps

5 0

3 years ago

Find the angle between u = (8.- 3) and v = (-3,- 8) Round to the nearest tenth of a degree.

Nimfa-mama [501]

Answer:

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

$|u|=\sqrt{(8)^2 + (-3)^2} \\\\|u|=\sqrt{64 + 9}\\\\|u|=8.544$

The module of v is:

$|v|=\sqrt{(-3)^2 + (-8)^2} \\\\|u|=\sqrt{9 + 64}\\\\|u|=8.544$

Now we calculate the scalar product between both vectors

$u*v = 8*(-3) + (-3)*(-8)\\\\u*v = -24+ 24=0$

Finally we know that the scalar product of two vectors is equal to:

$u*v = |u||v|*cos(\theta)$

Where $\theta$ is the angle between the vectors u and v. Now we solve the equation for $\theta$

$0 = 8.544*8.544*cos(\theta)\\\\0 = cos(\theta)\\\\\theta= arcos(0)\\\\\theta=90\°$

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

5 0

3 years ago

Read 2 more answers