CAN SOMEONE PLEASE HELP MEEEE!!!!
1 answer:
<u>Question</u><u>:</u>
In triangle JKL, the measure of angle L = 90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of angle J?
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<u>Solution</u><u>:</u>
The triangle JKL should look like that in the attachment.
Cosine of J = adjacent side/hypotenuse
= LJ/KJ
= 35/37
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Answer:
x ≈ 14.87
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )
x = ≈ 14.87 ( to the nearest hundredth )