Answer:
Option A is correct
The function 
has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;
Step-by-step explanation:
the coefficients are the whole numbers accompanied by the variable. would be: 3, 5, 1, 13
Answer:
B. 
Step-by-step explanation:
{y = 2x - 3,5
{x -2y = −14
x - 2[2x - 3,5] = −14
x - 4x + 7 = −14
−3x + 7 = −14
- 7 - 7
__________
−3x = −21
___ ___
−3 −3
[Plug this back into both equations above to get the y-coordinate of 10,5]; 
* 10½ = 10,5
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Answer:
9.2705545e+13
Step-by-step explanation:
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