Using the z-distribution, it is found that a sample of 171 should be selected.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
For this problem, the parameters are:

Hence we solve for n to find the needed sample size.





n = 170.7.
Rounding up, a sample of 171 should be selected.
More can be learned about the z-distribution at brainly.com/question/25890103
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I think the mean of variable a is 4
Recipe 1 : 4 cups oj with 6 cups pineapple.....ratio of 4/6 reduces to 2/3
recipe 2 : 6 cups oj with 9 cups pineapple...ratio 6/9 reduces to 2/3
recipe 3 : 9 cups oj with 12 cups pineapple....ratio 9/12 reduces to 3/4
so recipe 1 and recipe 2 will taste the same because the ratios are the same...and recipe 3 will be the different tasting one because it has a different ratio mixture
Given:
Lamont cotton is 4% commission on the first 10,000 of monthly sales and 10% on all sales over 10,000.
Consider his last month sales is 38,000.
To find:
The total commission.
Solution:
4% commission on the first 10,000 of monthly sales is

Sales over 10,000 is

10% commission on all sales over 10,000 is

Now, the total commission is

Therefore, the total commission is 3,200.