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Lynna [10]
3 years ago
9

Two persons are to run a race, but one can run 10 meters per second, whereas the other can run 4 meters per second. If the slowe

r runner has a 75-meter head start, how long will it be before the faster runner catches the slower runner, if they begin at the same time?
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:12.5 seconds

Step-by-step explanation:hconsidering Runner 1 with a speed of 10m/s

and Runner 2 with a speed of 4 m/s

the equation of displacement for a uniform movement is

x=V*t

so x1=V1*t

and x2=V2*t

and the problem condition is x2=x1+75m

so we proceed to solve the equations.

from equation 2 t=x2/V2

substituting in equation 1 we have

x1=V1(x2/V2) and then the 3 equation

x1=V1((x1+75m)/v2

finally x1=75*(V1/(V2-V1)) =75*(10/(10-4))=125m

then t=(x1/v1)=125/10=12.5 seconds

Allisa [31]3 years ago
3 0

Answer:

12.5 seconds

Step-by-step explanation:

Speed of the first person = 10 meter per second

Speed of the second person = 4 meter per second

Relative velocity of faster person = 10 - 4 = 6 meter per second

since distance between both the person is = 75 meter.

Therefore, time to cover this distance by faster person = \frac{Distance}{Speed}

\frac{75}{6}

= 12.5 seconds.

Faster runner catches the slower runner after 12.5 seconds.

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