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3 years ago

Can anybody tell what this is

Mathematics

1 answer:

Rzqust [24]3 years ago

7 0

The answer is c...the domain is the set of all real numbers greater than -4

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Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.

Step2247 [10]

Answer:

Remember, the expansion of $(x+y)^n$ is $(x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k$ , where $\binom{n}{k}=\frac{n!}{(n-k)!k!}$ .

Then,

$(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k$

Then, the coefficient of the term $p^{6-k}q^k$ is $\binom{6}{k}5^{6-k}2^k$

a) since 6-k=2, then k=4. So the coefficient of $p^2q^4$ is

$\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000$

b) since 6-k=5, then k=1. So, the coefficient of $p^5q$ is

$\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500$

c) since 6-k=3, then k=3. So, the coefficient of $p^3q^3$ is

$\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000$

6 0

3 years ago

HELP!!! ASAP!

Feliz [49]

The solution to given system of equations is $(x, y) = (\frac{-15}{263} , \frac{-115}{263})$

The given equation has one solution

Solution:

Given system of equations are:

12x - 13y = 5 --------- eqn 1

x = 23y + 10 --------- eqn 2

We have to solve the system of equations by substitution

Substitute eqn 2 in eqn 1

12(23y + 10) - 13y = 5

276y + 120 - 13y = 5

263y = 5 - 120

263y = -115

$y = \frac{-115}{263}$

Substitute the above value of "y" in eqn 2

$x = 23 \times \frac{-115}{263} + 10\\\\x = \frac{-2645}{263} + 10\\\\x = \frac{-2645 + 2630}{263}\\\\x = \frac{-15}{263}$

Thus the solution to given system of equations is $(x, y) = (\frac{-15}{263} , \frac{-115}{263})$

Thus the given equation has one solution

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3 years ago

Whos your favorite person?

sp2606 [1]

My mommmmmmmmmmmmmmmmmmmmmmmmmm

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3 years ago

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25 pounds of dog food at $1.25 per pound

RoseWind [281]

Answer:

$31.25

Step-by-step explanation:

multiply 25 by 1.25

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A=bh, for b (an area formula)

Katyanochek1 [597]

If you are trying to make B the subject, you have to divide both sides by 'h' because we need to get rid if 'h' to get 'b' on it's own, and you do the opposite of times - which is to divide. Once you divide both sides by h, you should end up with this:

A/h=b

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3 years ago