Step-by-step explanation:

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
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Answer:
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Step-by-step explanation:
Just answer the question
Answer:
102
Step-by-step explanation:
Since we know that the numbers are two consecutive even numbers, we can write an equation like this where n represents the 2 numbers.
n + (n+2) = 206
Simplify the left side:
n + (n+2) = 206 -----> 2n+2 = 206
Subtract 2 from both sides:
2n = 206-2 -----> 2n = 204
Now divide 204 by 2:
n = 204/2 -----> n = 102
Answer:
It is one-half the area of a rectangle with sides 4 units × 3 units
Step-by-step explanation:
One side of the triangle is on the line y = 2 between points x=2 and x=6. So, that side has length 6-2 = 4.
The opposite vertex has y-value 5, so is 3 units away from the line y = 2.
The area of the triangle can be considered to have a base of 4 and a height of 3. In the formula ...
A = (1/2)bh
we find the area to be ...
A = (1/2)×(4 units)×(3 units) . . . . triangle area
__
A rectangle's area is the product of its length and width. So, a rectangle that is 4 units by 3 units will have an area of ...
A = (4 units)×(3 units) . . . . rectangle area
Comparing the two area formulas, we see that the triangle area is 1/2 the area of the rectangle with sides 4 units × 3 units.
Answer:
V = 192 m^3
Step-by-step explanation:
The volume of a cuboid is given by
V = l*w*h
V = 4m * 6m *8m
V = 192 m^3