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Marizza181 [45]
3 years ago
14

Find all constants α such that the vectors (α, 4) and (α, 5) are parallel.

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer:

\alpha_{2} = \frac{5}{4}\cdot \alpha_{1}, for all \alpha_{1} \in \mathbb{R}

Step-by-step explanation:

Vectors are parallel to each other if:

\vec u = \beta \cdot \vec v

(\alpha_{2}, 5) = (\beta\cdot \alpha_{1}, \beta \cdot 4)

The value of \beta is:

\beta = \frac{5}{4}

Then, the following relationship is found:

\alpha_{2} = \frac{5}{4}\cdot \alpha_{1}, for all \alpha_{1} \in \mathbb{R}

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Plz help!!
Alexxx [7]

Answer:

there is a 3/4 chance that they pass will be completed, 3/4=75%.

Step-by-step explanation:

Thats all I got, I hope this may help tho! :)

6 0
3 years ago
Read 2 more answers
Find AB when given angle B 64 degress angle C 75 degrese and side a 19
jeka94

Answer:

about 28

Step-by-step explanation:

you have to use the sine rule = side you know * ( sin of angle opposing the side you want to know / sin of angle opposing the side you know)

AB = 19* (sin 75/ sin ( 180 -75-64) )

AB = 19 * ( sin 75 / sin 41) ≈ 27.9739...

4 0
3 years ago
How many times were you able to transfer any contents of the cone into the cylinder? What comparison can you make between the vo
STatiana [176]
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4 0
3 years ago
A cargo van is carrying 20 identical steel cylinders.Each cylinder contains compressed oxygen.Altogether,the cylinders weigh 1/2
sergeinik [125]
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5 0
3 years ago
Find four geometric means between 25 and 800.
SVEN [57.7K]

Actually, you have to find four missed terms of geometrical sequence. Denote

a_1=25,\\ a_6=800

and r - ratio, then

a_2=a_1\cdot r=25r,\\a_3=a_1\cdot r^2=25r^2,\\a_4=a_1\cdot r^3=25r^3,\\a_5=a_1\cdot r^4=25r^4,\\a_6=a_1\cdot r^5=25r^5.

Since a_6=800, you have that 800=25r^5, then

r^5=\dfrac{800}{25} =32,\\r=2.

Now substitude r=2 in each of unknown 4 terms:

a_2=25\cdot 2=50,\\a_3=25\cdot 2^2=100,\\a_4=25\cdot 2^3=200,\\a_5=25\cdot 2^4=400.

Answer: four geometric means between 25 and 800 are 50, 100, 200, 400.

8 0
3 years ago
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