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Marizza181 [45]
3 years ago
14

Find all constants α such that the vectors (α, 4) and (α, 5) are parallel.

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer:

\alpha_{2} = \frac{5}{4}\cdot \alpha_{1}, for all \alpha_{1} \in \mathbb{R}

Step-by-step explanation:

Vectors are parallel to each other if:

\vec u = \beta \cdot \vec v

(\alpha_{2}, 5) = (\beta\cdot \alpha_{1}, \beta \cdot 4)

The value of \beta is:

\beta = \frac{5}{4}

Then, the following relationship is found:

\alpha_{2} = \frac{5}{4}\cdot \alpha_{1}, for all \alpha_{1} \in \mathbb{R}

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Five times the sum of number and 27 is greater than or equal to six times the sum of that number and 26. What is the
raketka [301]

Answer:

x \geq -21

Step-by-step explanation:

Let the number be x.

Translating the word problem into an algebraic equation, we have;

5(x + 27) \geq 6(x + 26)

Opening the bracket, we have;

5x + 135 \geq 6x + 156

Collecting like terms, we have;

6x - 5x \geq 135 - 156

x \geq -21

8 0
3 years ago
Round to the nearest whole number.
faltersainse [42]

Answer:

Step-by-step explanation:

4

3 0
3 years ago
A rectangular bedroom is 4 ft longer than it is wide. Its area is 252 ft2. What is the width of the room?
Ksenya-84 [330]

Answer:

14 ft

Step-by-step explanation:

Given:

  • Bedroom is 4 ft longer than it is wide.
  • Area is 252 ft².

Let x = width of the bedroom:

  • width = x ft
  • length = (x + 4) ft

Therefore:

\begin{aligned}\textsf{Area of a rectangle} & = \sf width \times length\\\implies 252 & = x(x+4)\\252 & = x^2+4x\\x^2+4x & = 252\end{aligned}

To find the value(s) of x, complete the square.

Add the square of half the coefficient of the term in x to both sides:

\implies x^2+4x+\left(\dfrac{4}{2}\right)^2=252+\left(\dfrac{4}{2}\right)^2

\implies x^2+4x+4=256

<u>Factor</u> the perfect trinomial on the left side:

\implies (x+2)^2=256

<u>Square root</u> both sides:

\implies x+2= \pm \sqrt{256}

\implies x+2= \pm 16

Therefore:

\implies x=-2+16=14

\implies x=-2-16=-18

As width cannot be negative, the width of the room is 14 ft.

3 0
2 years ago
An image of a parabolic lens is projected onto a graph.The y-intercept of the graph is (0, 90), and the zeros are 5 and 9. Which
Gnesinka [82]

Step-by-step explanation:

If the zeros are 5 and 9, then the equation will have the form:

y = a (x–5) (x–9)

We know the point (0, 90) is on the curve, so we can use this to find the coefficient a:

90 = a (0–5) (0–9)

90 = 45a

a = 2

y = 2 (x – 5) (x – 9)

6 0
4 years ago
Read 2 more answers
2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16
Masja [62]

Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}

With this equation, we can factor each equation:

\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}

We can cancel out like terms since they would be dividing each other:

\frac{x-4}{2x-2}

8 0
3 years ago
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