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sweet-ann [11.9K]
3 years ago
10

Help for brainliest!

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0

Answer:

I believe it's d but I could be wrong but I'd try it

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FUNNY ONE ANSWER ! !!!!!!!!!
lakkis [162]

Answer: trapezoid

Step-by-step explanation: A <u>trapezoid</u> is a quadrilateral

with exactly one pair of parallel sides.

Also, quadrilaterals are two-dimensional shapes.

So it's impossible that's its 3-d.

7 0
3 years ago
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Will give brainliest pls answer correctly
Minchanka [31]
The answer is
R=65-60p
r=5(13-12p)
5 0
3 years ago
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Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point) a 2 b 3 c All real numbers d No solution
Fofino [41]

-2(x + 3) = -2(x + 1) - 4

-2x - 6 = -2x - 2 - 4        <em>distributed -2 on the left and on the right</em>

-2x - 6 = -2x - 6

<u>+2x     </u>   <u>+2x      </u>

     -6 =        -6

        TRUE

Since this is a true statement, there are infinite solutions (aka All Real Numbers)

Answer: C

8 0
3 years ago
The sample loses 1/3of it’s mass every ___ days
eimsori [14]

Answer:

The sample loses \frac{1}{3} of its mass every \frac{1}{3} days.

Step-by-step explanation:

Expression that shows the relation between final mass of the element after 't' days is,

M(t) = 900(\frac{8}{27})^t

If M(t) = two third of the initial mass [After the loss of one third of the initial mass remaining mass of the element = 1 - \frac{1}{3} = \frac{2}{3}rd of the initial mass]

900\times \frac{2}{3}=900(\frac{8}{27})^t

\frac{2}{3}=(\frac{8}{27})^t

\frac{2}{3}=[(\frac{2}{3})^3]^t

(\frac{2}{3})^1=(\frac{2}{3})^{3t}

By comparing powers on both the sides

3t = 1

t = \frac{1}{3} day

Therefore, The sample loses \frac{1}{3} of its mass every \frac{1}{3} days.

5 0
3 years ago
I really don't understand this can someone please help?
BabaBlast [244]

Answer: Could just answer for these two, sorry

b)48

d) 127

Step-by-step explanation:

b) EC=180

180= EA+AB+BC

180=79+53+AB

AB=180-132=48

d) EA+AB=79+48=127

3 0
4 years ago
Read 2 more answers
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