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Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
y = 2x - 3
Step-by-step explanation:
y - - 3 = 2(x-0)
y + 3 = 2x
y = 2x -3
Answer:
- 8p - 80
Step-by-step explanation:
Given
4(- 15 - 3p) - 4(- p + 5) ← distribute both parenthesis
= - 60 - 12p + 4p - 20 ← collect like terms
= - 8p - 80
Answer:
10500 dollars
Step-by-step explanation:
350,000 * .03 = 10500