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3 years ago

What is the midpoint of the line segment graphed below?

Mathematics

1 answer:

JulsSmile [24]3 years ago

8 0

Answer:

a) (4,7/2)

Step-by-step explanation:

Midpoint Formula:

[(-1+9)/2], [(2+5)/2]

(8/2, 7/2) = (4, 7/2)

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12. Carmen multiplied a non-zero rational number by its additive inverse. Which statement about the product must be true?

nignag [31]

Answer:

Option C. The product was negative.

Step-by-step explanation:

Let the non-zero rational number is = $\frac{x}{y}$

So, its additive inverse = $-\frac{x}{y}$

The result of multiplication the non-zero rational number by its additive inverse = $\frac{x}{y} *-\frac{x}{y} =-\frac{x^2}{y^2}$

We will check the options:

A. The product was the multiplicative inverse of the original number.

Wrong because the product = $\frac{x}{y} *-\frac{x}{y} =-\frac{x^2}{y^2}$

B. The product was the additive inverse of the original number.

Wrong because the product = $\frac{x}{y} *-\frac{x}{y} =-\frac{x^2}{y^2}$

C. The product was negative.

True

D. The product was positive.

Wrong because the product was negative.

So, the answer is option C.

6 0

3 years ago

Evaluate integral_S integral (x - 2y + z) dS. S: z = 16, x^2 + y^2 le 1

vovikov84 [41]

$S$ is the disk of radius 1 parallel to the $x,y$ -plane and lying in the plane $z=16$ . Parameterize this surface by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+16\,\vec k$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec r_u\times\vec r_v=u\,\vec k$

(the orientation doesn't matter because this is a scalar surface integral)

Then

$\displaystyle\iint_S(x-2y+z)\,\mathrm dS=\iint_S(u\cos v-2u\sin v+16)\|u\,\vec k\|\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^1(u^2(\cos v-2\sin v)+16u)\,\mathrm du\,\mathrm dv=\boxed{16\pi}$

5 0

3 years ago

If it takes 6.3 pounds of seed to plant one acre of grass, how many acres can be planted with 6.93 pounds of seed

ArbitrLikvidat [17]

Answer:

1.1 acre land

Step-by-step explanation:

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3 years ago

30 POINTS! Answer These Algebra 1 Questions ASAP!

MAXImum [283]

What is the question

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4 years ago

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Point A is located in which quadrent? A) l B) ll C)lll D) lV

Eduardwww [97]

Answer:

It is choice 3

Step-by-step explanation:

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3 years ago