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3 years ago

0.0000000006 in scientific notation???

2 answers:

4 0

When the number is smaller than 1, the decimal point has to move to the right, so the power of 10 is negative.
Answer: 6 x 10^-10

givi [52]3 years ago

3 0

6 × 10^-10

Hope this helps

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I need this answered please

Basile [38]

I think is gonna be B

3 0

3 years ago

Read 2 more answers

In a hospital there are 56 TB patients. The patients are grouped with respect to their ages.

zalisa [80]

Table:

Class Boundaries Frequency

5-10 8

10-15 9

15-20 15

20-25 10

25-30 8

30-35 6
 ----------
total 56

Average =

[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
---------------------------------------------------------------------------------------------------
 56

That is 1075 / 56 = 19.2

Answer: 19

5 0

3 years ago

Need help, please kfvleknfv

omeli [17]

Problem 18

Answers:

~P -> Q: "if it is not fall, then the leaves change colors"

~P -> ~Q: "if it is not fall, then the leaves don't change colors"

P -> ~Q: "If it is fall, then the leaves don't change colors"

Q -> ~P: "If the leaves change colors, then it is not fall"

----------

Explanation:

Simply replace each letter with the corresponding definition. We replace each P with "it is fall" and each ~P with "it is not fall". The squiggly line means "not". The same idea applies with Q and ~Q.

==========================================

Problem 19

Answer: Choice A) 134

----------

Explanation:

AB = CD

8x = 4x+24

8x-4x = 24

4x = 24

x = 6

BC = 18x+26

BC = 18*6+26

BC = 134

==========================================

Problem 20

Answer: Choice C) x = 5 and y = 11

----------

Explanation:

(anglePQR)+(angleRQS) = 90

(12x-2)+(6x+2) = 90

18x = 90

x = 5

angle TQU = 90

10y-20 = 90

10y = 110

y = 11

==========================================

Problem 21

Answer: 99

----------

Explanation:

The remote interior angles add to the exterior angle (remote interior angle theorem)

(angle RPQ) + (angle PQR) = angle PRS

(3x-29) + (7x-42) = 6x-3

10x-71 = 6x-3

10x-6x = -3+71

4x = 68

x = 68/4

x = 17

angle PRS = 6x-3

angle PRS = 6*17-3

angle PRS = 99

==========================================

Problem 22

Answer: 116

----------

Explanation:

Refer to the diagram below.

Solve 105+x = 180 to get x = 75

Solve 135+y = 180 to get y = 45

Solve x+y+z = 180 to get z = 60

Solve z+82+p = 180 to get p = 38

Solve p+78+q = 180 to get q = 64

Solve q+r = 180 to get r = 116

==========================================

Problem 23

Answer: B) between 4 and 44 inches

----------

Explanation:

We use a variation of the triangle inequality theorem here.

If p is the missing side length, then

24-20 < p < 24+20

4 < p < 44

So,

4 < XY < 44

The side XY cannot be 4 inches and it cannot be 44 inches either.

==========================================

Problem 24

4 Answers: A, B, C, D

----------

Explanation:

Same idea as problem 23

24-10 < x < 24+10

14 < x < 34

So we'll select values between 14 and 34, excluding each endpoint. Those values are x = 16, 18, 24, 26

In other words, only 12 and 34 are non-answers.

==========================================

Problem 25

Answer: C) 84 degrees

----------

Explanation:

The given exterior angle is 152 degrees

Subtract that from 180 to get the adjacent interior angle 180-152 = 28

Now let's find the missing angle of triangle DEB

D+E+B = 180

28+68+B = 180

96+B = 180

B = 180-96

B = 84

This is the measure of angle DBE

This is also the measure of angle ABC because the two angles are vertical angles.

Vertical angles are always congruent.

4 0

3 years ago

A * b = 3a - 2b 2*(6*4)= working please!!!

Pachacha [2.7K]

Answer:

A = 4

B = 2

2* (6 * 4) = 48

Please mark as brainliest if answer is right

Have a great day, be safe and healthy

Thank u

6 0

2 years ago

Read 2 more answers

Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dA R , where R is the region in the first quadrant betw

alexira [117]

Answer:

I = 1.47001

Step-by-step explanation:

we have the function

$f(x,y)=sin(x^2y^2)\\$

In polar coordinates we have

$x=rcos\theta\\y=rsin\theta$

and dA is given by

$dA=rdrd\theta$

Hence, the integral that we have to solve is

$I=\int \limt_2^4 \int \limit_0^{\pi /2}sin(r^4cos^2\theta sin^2\theta)rdrd\theta$

This integral can be solved in a convenient program of your choice (it is very difficult to solve in an analytical way, I use Wolfram Alpha on line)

I = 1.47001

Hope this helps!!!

7 0

3 years ago