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inna [77]
3 years ago
8

50 points! Please help you guys! I will mark brainliest and random answers will be reported

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

Slope of KL = (1-0)/(-3-0) = -⅓

Slope of JL = (3-0)/(1-0) = 3

The product of the slopes is -1, so L is a right angle. The orthocenter of a right triangle lies ON the triangle at the vertex of the 90° angle. Coordinates of orthocenter: (0,0)

:::::

DE is horizontal, so its altitude to F is the vertical line x=1. The altitude does not intersect segment DE, so the triangle is obtuse. The orthocenter of an obtuse triangle lies OUTSIDE of the triangle.

Slope of DF = (-2-2)/(-3-1) = 1

Altitude to E(-2,-2):

y+2 = -1(x+2)

y = -x-4

Orthocenter is Intersection of altitudes: =(1,-5).

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I need #1 done (show work) will give brainliest
allochka39001 [22]

Step-by-step explanation:

<u>Statement                                                        Reason                               </u>

∠5 and ∠7 are vertical angles                        Vertical angles theorem

m∠5 = m∠7                                                      Definition of vertical angles

m∠5 = -2(3x - 4), m∠7 = 3(x - 3) - 1                  Given

-2(3x - 4) = 3(x - 3) - 1                                       Substitution property of equality

-6x + 8 = 3x - 9 - 1                                            Distributive property

3x + 6x = 8 + 10                                               Addition property

9x = 18                                                              Addition property

x = 18/9                                                             Division property

x = 2                                                                  Proved

6 0
3 years ago
If the population of a particular country is growing at 3.2 % compounded​ continuously, how long will it take the population to
Lisa [10]

Answer:

It will take 34.33

Step-by-step explanation:

* Lets talk about the compound continuous growing

- Compound continuous growing can be calculated using the formula:

 A=Pe^{rt}

# A = the future value

# P = the initial amount

# r = the growing rate  in decimal

# t = the time

* Lets solve the problem

- The population of a particular country is growing at 3.2 %

 compounded​ continuously

∴ r = 3.2/100 = 0.032

- We need to find how long will it take the population to triple​

∵ The initial population is P

∴ A = 3P

∵ A=Pe^{rt}

∴ 3P=Pe^{0.032t}

- Divide both sides by P

∴ 3=e^{0.032t}

- Insert ㏑ for both sides

∴ ln(3)=ln(e^{0.032t})

- Remember ln(e^{n})=n

∴ ㏑(3) = 0.032t

- Divide both sides by 0.032

∴ t = ㏑(3)/0.032 = 34.33

* It will take 34.33

8 0
3 years ago
At the movie theatre, child admission is $5.30 and adult admission is $8.40. On Wednesday, three times as many adult tickets as
aleksley [76]

Answer:

39

Step-by-step explanation:

Let x = number of child tickets sold.

Cost of x child tickets is x * 5.30 = 5.3x.

"three times as many adult tickets as child tickets were sold"

Number of adult tickets sold: 3x

Cost of 3x adult tickets is 3x * 8.40 = 25.2x

Cost of all tickets is 5.3x + 25.2x = 30.5x

Cost of all tickets is $1189.50

30.5x = 1189.5

x = 1189.5/30.5

x = 39

Answer: 39

6 0
4 years ago
Suppose I had a tower that stood two Earth radii tall from the surface of the Earth to the top I start on the ground with a scal
weqwewe [10]

Answer: The rock would still weigh 90lbs

Step-by-step explanation:

No, weight has being proven to reduce by the further you move from the center of the Earth. But since even the tallest buildings in the world or tallest mountains are a tiny fraction of the Earth’s radius, the difference in weight won’t be something that can be measured as it’s a tiny fraction. So the mass of the rock doesn’t change what changes is the gravitational force ( g ). So the rock would still end up weighing 90lbs even at the top of the tower because it is still within the earths atmosphere.

4 0
3 years ago
(14+13n+3n^3)+(2+4n+9n^3)
Sliva [168]

Answer:

=12n3+17n+16

i hope this helps :)

8 0
4 years ago
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