Can anyone help with this asap? tysm
1 answer:
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Answer:
The diameter of the target is
Step-by-step explanation:
we know that
In this problem the distance from the center of an archery target to the outside edge of the target is equal to the radius of the target
so
Remember that
The diameter is two times the radius
substitute
Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:
a)
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082
b)
The area to the left of z=3.00 is 0.9987
c) The z-value of 1200 is 0
The area to the left of 0 is 0.5
The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is
d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e)
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1