I got the answer to be 42.
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

Answer:
9 songs are purchased.
Step-by-step explanation:
10.35 / 1.15 = 9
Answer:
see explanation
Step-by-step explanation:
(a)
The angle around the centre O of the circle = 360°, then
∠ AOB = 360° - 260° = 100°
Δ AOB is isosceles ( the radii OA and OB are congruent )
The altitude from O bisects ∠ AOB , thus
y = 50°
Since the triangle is isosceles the 2 base angles are congruent, so
x =
=
= 40°
(b)
∠ POR = 360° - 254° = 106°
Δ POR is isosceles (the radii OP and OR are congruent ) , then
the 2 base angles are congruent , thus
a =
=
= 37°
Let, the numbers = x, (x+2), (x+4)
x+x+2+x+4 = 63
3x+6=63
3x=57
x = 19
so, smallest number would be 19