Plzz help with an appropriate answer

.If you dye 1/3 of it blue, ¼ pink and 2/5 black, how much of your original hair colour is left?

sineoko [7]

Answer:

You have 1/60 of the original hair color left

Step-by-step explanation:

Add up the fractions

1/3 + 1/4 + 2/5

Get a common denominator of 60

1/3 * 20/20 + 1/4 * 15/15 + 2/5 * 12/12

20/60 + 15/60 + 24/60

59/60

The total is 1 or 60/60

60/60 - 59/60

1/60

You have 1/60 of the original hair color left

8 0

3 years ago

Find the missing factor $6.50. =$65

babymother [125]

1) $65 ÷ $6.50 = $10
2) Check Work: $10 × $6.50 = $65
$10 is your missing factor :)
Hope This Helps :)

6 0

4 years ago

Read 2 more answers

Which question is a statistical question?

Ray Of Light [21]

Answer:

How long does it take the students in my class to travel to school?

Step-by-step explanation:

A statistical question is one that can be answered by collecting data and where there will be variability in that data.

7 0

3 years ago

From a thin piece of cardboard 50 in. by 50 in., square corners are cut out so that the sides can be folded up to make a box. Wh

mixer [17]

Answer:

When dimension of box is 33.33 inches × 33.33 inches ×8.33 then its volume is maximum and is 9259.26 cubic inches.

Step-by-step explanation:

Let h be the length (in inches) of the square corners that has been cut out from the cardboard and that would be the height of the cardboard box.

Since the squares have been cut from cardboard, both sides of the cardboard would reduce by 2h.

Thus, The dimension of box is (50 – 2h) × (50 – 2h) × h in dimensions.

The volume V of rectangular box = (Length × Breadth × Height) cubic inches.

$V=(50-2h) \times (50-2h) \times h$

$V=(50-2h)^2 \times h$ ..............(1)

Using $(a-b)^2=a^2+b^2-2ab$

$V=h(2500+4h^2-200h)$

$V=2500h+4h^3-200h^2$

For obtaining a box of maximum volume, maximize V as a function of h.

Differentiate both sides with respect to h,

$\frac{dV}{dh}=2500+12h^2-400h$

$\frac{dV}{dh}=4(625+3h^2-100h)$

Solving quadratic equation, $625+3h^2-100h$

$\frac{dV}{dh}=4(3h^2-25h-75h+625)$

$\frac{dV}{dh}=4(h(3h-25)-25(3h-25))$

$\frac{dV}{dh}=4((h-25)(3h-25))$

For maximum, $\frac{dV}{dh}=0$

thus, $4((h-25)(3h-25))=0$

⇒ $h= 25$ or $h=\frac{25}{3}$

Now check (1) for $h= 25$ and $h=\frac{25}{3}$ .

$h= 25$ is not possible as when h is 25 inches then length and breadth becomes 0.

When $h=\frac{25}{3}$ .

(1) ⇒ $V=(50-2(\frac{25}{3}))^2 \times\frac{25}{3}=9259.2592593$

This is the maximum volume the box can assume.

Thus, when dimension of box is 33.3 inches × 33.3 inches ×8.3 then its volume is maximum and is 9259.26 cubic inches.

6 0

3 years ago

If the areas of two similar triangles are equal, prove that they are congruent

Ronch [10]

Refer the attached image for the answer

HOPE SO IT HELPS YOU

3 0

3 years ago