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Bad White [126]
3 years ago
12

Find the factors 4x^2+9

Mathematics
1 answer:
Vlad [161]3 years ago
7 0

Step-by-step explanation:

So 4x2+9 has no linear factors with Real coefficients. It is possible to factor it with Complex coefficients.

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali
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Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}

rewrite the root

\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}

then cancel the terms that are cubes and bring them out of the root

\sqrt[3]{80}=2\sqrt[3]{10}

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sergij07 [2.7K]

Answer:

(6.5,3)

please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment.....

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Read 2 more answers
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