a) Proof by contradiction is different from traditional proof as it accepts a single example showing that a statement is false, instead of having the need to derive a general relationship for all input values.
b) The statement is true by contradiction as the sum of the measures is of 160º, and not 180º.
<h3>What are supplementary angles?</h3>
Two angles are called supplementary angles if the sum of their measures has a value of 180º.
The measures of the angles in this problem are given as follows:
Then the sum of the measures of this angles is given as follows:
90 + 70 = 160º.
Which is a different sum of 160º, confirming the statement that the angles are not supplementary by contradiction.
A similar problem, involving proof by contradiction and supplementary angles, is presented at brainly.com/question/28889480
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Answer:
617 ^ 15
Step-by-step explanation:
If the bases are the same when multiplying, add the exponents
617 ^ 9 * 617^6
617 ^(9+6)
617 ^ 15
Answer:
3,200 is first divided by 2 which is smallest prime number . Then the answer is get 1,600 . Again this number is divided by 2 then answer is 800 . This step is continues for all time . So , it is again divided by 2 then answer comes 400 then divided answer comes 200. Then again divided by 2 then answer is 100 and again divided by 2 then answer is 50 again divided by 2 then answer is 25. now we cannot divided by 2 this number 50. Then what to do? we have to use prime number .so we have to divided by 5 then answer is 5. In last ,for checking we have to multiply all this prime number to check this answer.
Answer:
Step-by-step explanation:
Let 
. We have that 
if and only if we can find scalars 
such that 
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for 
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are 
, but note that for this values, the third equation doesn't hold (3+2 = 5 
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are 
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
1/2(2 + 6) is another one boi
