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dangina [55]
3 years ago
15

Please help me out you guys

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
5 0

Answer:

okok I willl hel0 you out

aleksandrvk [35]3 years ago
3 0

Answer:

It's blurry. Send a clearer picture

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Write an expression that is equivalent to -2/5(15 - 20d +50)<br> Explain please!:)
valina [46]

Answer:

-26 + 4/5d

Step-by-step explanation:

-2/5 ( 15 - 2d + 50)

= -2/5 ( 65 - 2d)

= -2/5 * 65 - (-2/5) * 2d

= -26 - (-4/5d)

= -26 + 4/5d

3 0
2 years ago
Help please (will chose brainliest)
goldfiish [28.3K]

Answer:

LEts start with 10^1

If we have positive exponent then we add zeros

10^1= 10

10^2=100 (Put 2 zeros because exponent is 2)

10^3=1000 (Put 3 zeros because exponent is 3)

10^4=10000 (Put 4 zeros because exponent is 4)

10^5=100000 (Put 5 zeros because exponent is 5)

For negative exponent , we make a fraction . we put 1  at the top always and number as the bottom

10^{-1}=\frac{1}{10} (Put 1 zero at the bottom because exponent is -1)

10^{-2}=\frac{1}{100} (Put 2 zeros at the bottom because exponent is -2)

10^{-3}=\frac{1}{1000} (Put 3 zeros at the bottom because exponent is -3)

3 0
3 years ago
HELP ME LLEASE WUIZ OMG WHAT ARE THE CORDS? 30 points
wariber [46]

Answer: -1/2 and 1/3

Step-by-step explanation:

3 0
3 years ago
7 cards are drawn from a standard deck of 52 playing cards. How many different 7-card hands are possible if the drawing is done
Vladimir [108]

Answer:

The number of different 7 card hands possibility is  133784560

Step-by-step explanation:

The computation of the number of different 7 card hands possibility is shown below:

Here we use the combination as the orders of choosing it is not significant

So,

The number of the different hands possible would be

= ^{52}C_7

= 52! ÷ (7! × (52 - 7)!)

= 133784560

Hence, the number of different 7 card hands possibility is  133784560

4 0
2 years ago
Solve the inequality 1 2p + 7 ) 1 39​
Llana [10]

Answer: p=11

Step-by-step explanation:

12p+7)139

-7 -7

12p)132

÷12 ÷12

P)11

6 0
3 years ago
Read 2 more answers
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