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Oksanka [162]
3 years ago
7

A car uses 5 2/3 gallons of gas for a 2 hour trip. how many gallons were used each hour

Mathematics
1 answer:
ddd [48]3 years ago
3 0
It would use 2.83 gallons of gas for a 2 hour trip
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(SSS, SAS, AAS, ASA, HL)<br><br> Help me plzzzz
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The answer is HL. We know this because it is a right triangle (:
7 0
3 years ago
What operation do you use to convert 50 cups to gallons?
zzz [600]
Division can be used. For example

50/16=3.125gallons

or you could use multiplication

50*1/16=3.125gallons


5 0
2 years ago
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A block of wood has a mass of 6.0 g and a volume of 12.0 cm^3 . What is the density of the block of wood?
White raven [17]
Number 1 or also called a half
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2 years ago
Someone please help me with this question !!!!
Lyrx [107]

Answer:

34.3 in, 36.3 in

Step-by-step explanation:

From the question given above, the following data were obtained:

Hypothenus = 50 in

1st leg (L₁) = L

2nd leg (L₂) = 2 + L

Thus, we can obtain the value of L by using the pythagoras theory as follow:

Hypo² = L₁² + L₂²

50² = L² + (2 + L)²

2500 = L² + 4 + 4L + L²

2500 = 2L² + 4L + 4

Rearrange

2L² + 4L + 4 – 2500 = 0

2L² + 4L – 2496 = 0

Coefficient of L² (a) = 2

Coefficient of L (n) = 4

Constant (c) = –2496

L = –b ± √(b² – 4ac) / 2a

L = –4 ± √(4² – 4 × 2 × –2496) / 2 × 2

L = –4 ± √(16 + 19968) / 4

L = –4 ± √(19984) / 4

L = –4 ± 141.36 / 4

L = –4 + 141.36 / 4 or –4 – 141.36 / 4

L = 137.36/ 4 or –145.36 / 4

L = 34.3 or –36.3

Since measurement can not be negative, the value of L is 34.3 in

Finally, we shall determine the lengths of the legs of the right triangle. This is illustrated below:

1st leg (L₁) = L

L = 34.4

1st leg (L₁) = 34.3 in

2nd leg (L₂) = 2 + L

L = 34.4

2nd leg (L₂) = 2 + 34.3

2nd leg (L₂) = 36.3 in

Therefore, the lengths of the legs of the right triangle are 34.3 in, 36.3 in

5 0
2 years ago
A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3
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Just use your equation and sub in 1.5 for x (thee time) to find y (the height at that time). You get a height of 15.5 when the time is 1.5 seconds
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