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2 years ago

When would there be only four different equations for a set of math mountain numbers give an example

Mathematics

1 answer:

Kipish [7]2 years ago

5 0

Most have only 4 different equations.
For example,
6+8=14
8+6=14
14-6=8
14-8=6

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goldfiish [28.3K]

Answer:

The volume of can A is half the volume of can B.

Step-by-step explanation:

Given

Can A and Can B

Required

The true statement

For Can A, we have:

$h =8$

$r = 0.5$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_A = \pi * 0.5^2 * 8$

$V_A = \pi * 2$

$V_A = 2\pi$

For Can B, we have:

$h =4$

$r = 1$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_B = \pi * 1^2 * 4$

$V_B = \pi * 4$

$V_B = 4\pi$

So, we have:

$V_A = 2\pi$

$V_B = 4\pi$

By comparison, (d) is correct

4 0

3 years ago

Please help there is a attachment to this i think.

ser-zykov [4K]

Answer:

squrt6(84)

Step-by-step explanation:

By the law:

squrtn(a^m) = a^(m/n)

Best regards

5 0

2 years ago

WILL GIVE BRAINIEST Mr. Wright wants to tile a 5 ft by 5 ft square floor. He has three kinds of square tiles: 1 ft by 1 ft, 2 ft

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

8 0

2 years ago

I NEED HELP ASAP JUST TELL ME THE ANSWER THANK YOU WILL MARK BRAINLIEST !!

Strike441 [17]

Answer:

Step-by-step explanation:

$(6^{-4} \times 8^{-7})^{-9} =$

$= 6^{-4 \times (-9)} \times 8^{-7 \times (-9)}$

$= 6^{36} \times 8^{63}$

Answer: C

3 0

2 years ago

Read 2 more answers

Manuel and Felicia are comparing how much

Ilia_Sergeevich [38]

Answer:

y = 250 + 150x
y = 1650 - 200x

Step-by-step explanation:

Equation for Manuel:

y = 250 + 150x

Equation for Felicia:

y = 1650 - 200x

Solving we get:

250 + 150x = 1650 - 200x
150x + 200x = 1650 - 250
350x = 1400
x = 1400/350
x = 4 weeks

and

y = 250 + 150*4 = 250 + 600 = $850

After 4 weeks Manuel and Felicia will have equal amount of money- $850

5 0

2 years ago