Is A & C.
Explanation:
A. Median for sea turtles:
The set is odd, so median is the middle number - 4
The koi set had 10, even number, so the median for the koi is the average of the 2 middle: 4+3=3.5
Turtles > koi
C. The ages of koi are more spread out - 10. The turtles are only 5.
Answer:
A = 3(½(1 + 4)) = 7.5 units²
Step-by-step explanation:
area of a trapezoid is the average of the bases times the height.
h = -1 - (-4) = 3
base1 TR = 0 - (-1) = 1
base2 PA = 2 - (-2)) = 4
Answer:
a) e-0.03x(0.3-0.009x)
b) 33 hrs 20 min
c) 17.182
Step-by-step explanation:
Taking derivative of the above equation would give us the rate for change in donations :
hence
f'(x) = d/dx (0.3xe-0.03x)
using product rule of derivation where (uv)' = u'v +v'u
hence
f'(x) = (e-0.03x)d/dx(0.3x) + 0.3x*d/dx(e-0.03x)
= 0.3e-0.03x + 0.3x(-0.03)(e-0.03x)
f'(x) =0.3e-0.03x -0.009xe-0.03x
hence
a) rate of change in donations = e-0.03x(0.3-0.009x) taking exponent common
b) f'(x) = 0 according to statement
hence 0 = e-0.03x(0.3-0.009x)
0 = 0.3 - 0.009 x
which gives x = 33.33 hrs i.e after 33 hrs and 20 minutes rate of change of donations is 0.
c) donation level at the time is given by
f(x) = 0.3xe-0.03x
f(33.33) = 0.3 (33.33)e-0.03(33.33)
= 17.182
That is 17.182 thousand donations were made at that time.
