Perimeter (P) = 2 · Length(L) + 2 · Width (W) → P = 2L + 2W
Solve for either L or W (I am solving for L).
200 - 2W = 2L
(200 - 2W)/2 = L
100 - W = L
Area (A) = Length (L) · Width (W)
= (100 - W) · W
= 100W - W²
Find the derivative, set it equal to 0, and solve:
dA/dW = 100 - 2W
0 = 100 - 2W
W = 50
refer to the equation above for L:
100 - W = L
100 - 50 = L
50 = L
Dimensions for the maximum Area are 50 ft x 50 ft
Answer:
19.8 and 8/(sin(theta))+ 6/(cos(theta))
Step-by-step explanation:
If you make a table you can see that L_1 + L_2 gets larger as you increase theta prom pi/2 and decrease theta from pi/2. This means that pi/2 is the theta that will yield the smallest length for the ladder. Plugging this into L_1 + L_2 you get 19.8 (rounded to the nearest hundred)
C = 8/(sin(theta))+ 6/(cos(theta))
3/4x4=3 therefore she needs 3 cups of flour to make four batches of cookies : )
120 is the answer to your question
