How do I find the area of a regular octagon with perimeter of 48cm?
2 answers:
A≈173.82cm² that's the answer.
An octogon has 8 sides and each side is 48/8=6cm
The area of any regular polygon when the side length is known is:
A(n,s)=ns^2/(4tan(180/n)) in this case
A(8,6)=288/(4tan22.5)
A=173.82cm^2 (to nearest hundredth of a cm^2)
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