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3 years ago

How do I find the area of a regular octagon with perimeter of 48cm?

Mathematics

2 answers:

stepladder [879]3 years ago

8 0

A≈173.82cm² that's the answer.

koban [17]3 years ago

4 0

An octogon has 8 sides and each side is 48/8=6cm

The area of any regular polygon when the side length is known is:

A(n,s)=ns^2/(4tan(180/n)) in this case

A(8,6)=288/(4tan22.5)

A=173.82cm^2 (to nearest hundredth of a cm^2)

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3 years ago

from a window 24 feet above the ground, the angle of elevation to the top of another building is 38 degrees. The distance betwee

Delvig [45]

Answer:

The height of the building is $73.2\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

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$tan(38\°)=\frac{BC}{AB}$

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3 years ago

Please help, thanks!

Mamont248 [21]

((-4x^3)(y^4))^-3
--------------------------
(2xy^4)^-4
16x^4y^16
=------------------------
-64x^9y^12
-16y^4
=------------------------
64x^5
-y
=------------------------
4x^5

So the final answer is:

-y^4
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4x^5

(Btw if "^" is in front of a number, that means it is an exponent, so when your writing this on paper, just write it as a regular exponent without the "^". I had to do that since I'm on a computer.)

Hopefully this was helpful in some way.

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3 years ago

Please I Really Need Help.The coordinate plane below represents a city. Points A through F are schools in the city.

almond37 [142]

Answer:

Part A) The system of inequalities is

$x\geq2$ and $y\geq2$

Part B) In the procedure

Part C) The schools that Natalie is allowed to attend are A,B and D

Step-by-step explanation:

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions

we have

Points C(2,2), F(3,4)

The system of inequalities could be

$x\geq2$ -----> inequality A

The solution of the inequality A is the shaded area at the right of the solid line x=2

$y\geq2$ -----> inequality B

The solution of the inequality B is the shaded area above of the solid line y=2

see the attached figure N 1

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify point C

C(2,2)

Inequality A

$x\geq2$ -----> $2\geq2$ ----> is true

Inequality B

$y\geq2$ ------> $2\geq2$ ----> is true

therefore

Point C is a solution of the system of inequalities

Verify point D

F(3,4)

Inequality A

$x\geq2$ -----> $3\geq2$ ----> is true

Inequality B

$y\geq2$ ------> $4\geq2$ ----> is true

therefore

Point D is a solution of the system of inequalities

Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < −2x + 2. Explain how you can identify the schools that Natalie is allowed to attend.

we have

$y < -2x+2$

The solution of the inequality is the shaded area below the dotted line $y=-2x+2$

The y-intercept of the dotted line is the point (0,2)

The x-intercept of the dotted line is the point (1,0)

To graph the inequality, plot the intercepts and shade the area below the dotted line

see the attached figure N 2

therefore

The schools that Natalie is allowed to attend are A,B and D

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3 years ago