Question

How do I find the area of a regular octagon with perimeter of 48cm?

Answer 1

A≈173.82cm² that's the answer.

Answer 2

An octogon has 8 sides and each side is 48/8=6cm

The area of any regular polygon when the side length is known is:

A(n,s)=ns^2/(4tan(180/n)) in this case

A(8,6)=288/(4tan22.5)

A=173.82cm^2  (to nearest hundredth of a cm^2)