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4 years ago

Name the polynomial 200p - 30p^2m + 40m^3 based on the number of terms.

Mathematics

1 answer:

Sonbull [250]4 years ago

6 0

It's highest degree is 3, and has 3 terms, so this is a third-degree trinomial

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Ansley wants to drink at least 64 ounces of water per day, but no more than 72 ounces. How many ounces of water per day might sh

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64,65,66,67,68,69,70,71,72

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3 years ago

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Mr. Smith built a rectangular-shaped sandbox for his children, measuring 4 feet by 4 feet by 6 inches. Sand has a density of app

ehidna [41]

Answer:

To completely fill the sandbox will cost $56

Step-by-step explanation:

First, we calculate volume of the rectangular-shaped sandbox:

$V=long*with*height\\V=4feet*4feet*0.5feet\\V=8cubicfoot$

We know that density of sand is 100 pounds per cubic foot. Then, to fill the sand box that has a volume of 8 cubic foot, we calculate by rule 3:

1cubic foot..............100 pounds

8 cubic foot.............x pounds

$x=\frac{8*100}{1}$

$x=800 pounds$

We will need 800 pounds of sand to fill the sandbox, then we can calculate by rule 3 the number of bags needed and next the total cost of them:

50 pounds.......1bag

800 pounds.....x bags

$x=\frac{800*1}{50} \\x=16$

To calculate the cost:

1 bag ..................$3.50

16 bags.................$x

$x=16*3.50\\x=$56$

To completely fill the sandbox will cost $56

4 0

4 years ago

What is the solutions to the equation w/2w-3=4/w

labwork [276]

Answer:

{2, 6}

Step-by-step explanation:

w/2w-3=4/w is ambiguous. Did you mean

w 4

---------- = ------ ? If so, please enclose "2w - 3" inside parentheses.

2w - 3 w

Cross multiplying, we get w² = 8w - 12.

Putting this into standard form, we get:

w² - 8w + 12 = 0, which factors into (w - 2)(w - 6) = 0.

The solutions are found by setting each factor = 0 separately and solving the resulting equations for w: {2, 6}.

7 0

3 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir

Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, we find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

$\sigma = \sqrt{484} = 22$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$5 = 1.96*\frac{22}{\sqrt{n}}$

$5\sqrt{n} = 43.12$

$\sqrt{n} = \frac{43.12}{5}$

$\sqrt{n} = 8.624$

$(\sqrt{n})^{2} = (8.624)^{2}$

$n = 74.4$

We need a sample size of at least 75.

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3 years ago

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P(red, blue, or green)

zhannawk [14.2K]

What is the question

4 0

4 years ago