Answer:
(1 cm)cos3πt
Step-by-step explanation:
Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft
where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.
Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations = 2 s
So, f = 3/2 s =1.5 /s = 1.5 Hz
Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm
h = Acos2πft
= (1 cm)cos2π(1.5Hz)t
= (1 cm)cos3πt
Answer:
Step-by-step explanation:
Given a ΔLMN.
Line LN is extended to point O.
such that:
and
To find:
Solution:
Kindly refer to the attached image for the given triangle and dimensions of angles.
Let us recall the external angle property of a triangle:
The external angle of a triangle is equal to the sum of two opposite internal angles.
i.e.
Putting the value of 
in 
.
I would need more information to help you. Like the numbers of hours worked, amount of money made, and the statements.
Answer:
12 is missing
Step-by-step explanation:
