PART A
s = the number of packets of strawberry wafers ;
c = the number of packets of chocolate wafers ;
3 × s + 1 × c = 30 ;
s + c = 22 ;

PART B

The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.

c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;

4 0

3 years ago

-3x +2y= 4 4x-13y=5 solve by elimination

Svet_ta [14]

I am better at substitution, but you want to get the equations as similar as possible, but are the opposite, so you can cancel it out.

4 0

3 years ago