Answer: the equation is 2n-10
You are not giving much information so the assumption is the base is 2 = meters and the height is 3 meters.<span>
Find total area of a regular pyramid with base of 2 and altitude of 3
</span>
Surface Area = 16.64911 m²
Answers:
14 + 18 ÷ 2 x 18 – 7 = 169
- 14 + 9 * 18 - 7
- 14 + 162 - 7
- 169
60 – 9 x 8 ÷ 8 x 6 = 6
- 60 - 72 / 8 * 6
- 60 + -216/4
- 60 - 54
- 6
15 x 10 + 12 ÷ 3 + 9 = 163
- 150 + 12 / 3 + 9
- 150 + 4 + 9
- 163
(10 ÷ 5)3 + 100 – 9 x 11 = 7
- 2 * 3 + 100 - 9 * 11
- 6 + 100 - 99
- 7
8 x 4 + 9 – 9 + 18 = 50
- 32 + 9 - 9 + 18
- 41 - 9 + 18
- 32 + 18
- 50
3 x 8 x 2 – 42 + 5 = 11
- 24 * 2 - 42 + 5
- 48 - 42 + 5
- 11
<em>i hope this helps, good luck :)</em>
Answer: d = ±10
<u>Step-by-step explanation:</u>
169 = 
+ 
169 = (12)² + 
169 = 144 +
25 =
100 = d²
√100 = √d²
±10 = d
we know that
m∠SQR+x=
-------> by supplementary angles
so
m∠SQR=
The sum of the internal angles of a triangle is equal to degrees
m∠SQR+m∠QSR+m∠SRQ=
substitute the values in the formula
m∠SQR+
+
=
m∠SQR=
degrees
<u>Find the value of x</u>
m∠SQR=
x=-m∠SQR
x=
x=
degrees
therefore
<u>the answer is</u>
the value of x is degrees
