$\frac{d}{dx} (sin~x)=cos~x\\\frac{d}{dx}(cos~x) =-sin~x\\\frac{d^2}{dx^2} (sin~x)=\frac{d}{dx} (cos~x)=- sin~x\\\frac{d^2}{dx^2} (cos~x)=\frac{d}{dx} (-sin~x)=-cos~x$

5 0

2 years ago

David borrow $700 from a loan shark, and agreed to pay back $1500 after 5 months. What is his monthly payment?

sesenic [268]

Does he have interest???

6 0

3 years ago

Read 2 more answers

Adel started her homework at 9:10 she finished at 9:45 how long did she spend in her homework

sukhopar [10]

She spent 35 minutes doing her homework

8 0

3 years ago

In the diagram, AB = 12, DX = 2.5, and BX = 5. Find CD. Show all work.

Naily [24]

I found your complete question in another source.
See attached image.
For this case what you should see is that you have two similar triangles.
We then have the following relationship:
((AB) / (BX)) = ((CD) / (DX))
We cleared CD:
CD = ((AB) / (BX)) * (DX)
Substituting the values:
CD = ((12) / (5)) * (2.5)
CD = 6
Answer:
CD = 6

5 0

3 years ago