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3 years ago

Which is a solution for the equation y = 4x + 3?

1 answer:

3 0

Point are set up (x,y) you sub the number for x into the equation and see if you get the number for y.
y=4x+3
y=4 (5)+3
y=20+3
y=23
so A isn't the answer

y=4 (17)+3
y=68+3
y=71
B isn't the answer

y=4 (4)+3
y=16+3
y=19
and because 4 is the x value for c and d and there can only be 1 y value for each x you're answer is C because when x=4 y =19 or (4,19)

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f(x)=3x^(4)-5x^(3)-5x^(2)+5x+2 The number 3 is an upper bound for the set of roots of this polynomial function True or False

Leona [35]

Answer: TRUE

Step-by-step explanation: The number 3 is an upper bound because use 3 as a multiplyer of each bcoefficient of the polynomial and at each multiple,subtract the next coefficient from it. if all result after subtraction show positive, then the number used is an upper bound. This method is known as the synthetic division.

3 3 -5 -5 5 2

0 9 12 21 78

3 4 7 26 80

7 0

3 years ago

NO LINKS OR FILES!

Archy [21]

(a) If the particle's position (measured with some unit) at time t is given by s(t), where

$s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}$

then the velocity at time t, v(t), is given by the derivative of s(t),

$v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}$

(b) The velocity after 3 seconds is

$v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}$

$\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}$

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

$\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|$

In interval notation, this happens for t in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt$

By definition of absolute value, we have

$|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)$

In part (d), we've shown that v(t) > 0 when -√11 < t < √11, so we split up the integral at t = √11 as

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt$

and by the fundamental theorem of calculus, since we know v(t) is the derivative of s(t), this reduces to

$s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}$

7 0

2 years ago

Help me fast 50 points!!!!!!!!

mihalych1998 [28]

Answer:

Step-by-step explanation:

There are 14 data points on the plot

The median is the middle value, which is between the 7th and 8th data points

Since it is even, we find the average of the 7th and 8th data points

Add the 7th and 8Th data points values and divide by 2

( 30+30)/2 = 60/2 = 30

The median is 30

7 0

3 years ago

Read 2 more answers

2<img src="https://tex.z-dn.net/?f=%20%203%5E%28x%2B7%29%20%3D%20%209%5E%28x-1%29" id="TexFormula1" title=" 3^(x+7) = 9^(x-1)"

DaniilM [7]

3(x + 7) = 9(x - 1)
3(x) + 3(7) = 9(x) - 9(1)
3x + 21 = 9x - 9
- 3x - 3x 
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 + 9 + 9
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4 0

3 years ago

Solve for the value of c. 100° (4c)

alexgriva [62]

The answer is 25 because 4 x 25 is 100

8 0

3 years ago