The interquartile range (IQR) is 20
You find this by subtracting the values of Q3 and Q1
Q3 is the right most edge of the box which is 45
Q1 is the left most edge of the box which is 25
IQR = Q3 - Q1 = 45 - 25 = 20
Side Note: The median is not 45. The median is actually 40 since this is the middle line of the box, which is in between 35 and 45
13 divided by 1 and 3/7=9 and 1/10
$9.10
Answer:
B
Step-by-step explanation:
Once you subtract both sides, the 4 is gone then the 10 is subtracted into a 6. You go to the 3x, and just like what you did to the 4 you do the opposite and divide the 3 by itself and the 6 by 3 as well.
Answer:
See Explanation
Step-by-step explanation:
a) Additive inverse of −2
- the additive inverse of a number a is the number that, when added to 'a', yields zero. This number is also known as the opposite (number), sign change, and negation.
- So the Additive inverse of -2 is 2. ∴ -2+2=0
b) Additive identity of −5
- Additive identity is the value when added to a number, results in the original number. When we add 0 to any real number, we get the same real number.
- -5 + 0 = -5. Therefore, 0 is the additive identity of any real number.
c) additive inverse of 3
- Two numbers are additive inverses if they add to give a sum of zero. 3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.
d). multiplicative identity of 19
- an identity element (such as 1 in the group of rational numbers without 0) that in a given mathematical system leaves unchanged any element by which it is multiplied
- Multiplicative identity if 19 is 1 only, since 19 x 1 = 19.
e) multiplicative inverse of 7
- Dividing by a number is equivalent to multiplying by the reciprocal of the number. Thus, 7 ÷7=7 × 1⁄7 =1. Here, 1⁄7 is called the multiplicative inverse of 7.
d) | 11-5|×|1-5|
- | 11-5|×|1-5| ⇒ I6I×I-4I ⇒ 6×4 ⇒ 24
