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2 years ago

Question 14 of 16

Mathematics

1 answer:

Goryan [66]2 years ago

6 0

B, because you would just assume the line continues forever on both sides.

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What is the proportional relationship represented by this table?

77julia77 [94]

Answer:

the constant of proportionality is 0.2 and it is a proportional relationship

Step-by-step explanation:

2 divided by 10 is 0.2

1 divided by 5 is 0.2

they have the same answer so they are proportional

since they have the answer 0.2 it

is there constant of proportionality

4 0

3 years ago

What is the answer of the expression 325-[4x(58-19)+(75 divided by 3

inna [77]

325 - [4(58 - 19) + (75 / 3)]

Divide:

325 - [4(58 - 19) + 25]

Distribute 4:

325 - [232 - 76 + 25]

Subtract:

325 - [156 + 25]

Add:

325 - [181]

Subtract:

144

4 0

3 years ago

How do you calculate percentage? Is there an easier way?

san4es73 [151]

Divide the numerator of the fraction by the denominator. the first two digits of the decimal is the percentage

6 0

4 years ago

Three angles of a quadrilateral are 75 degrees, 90 degrees, and 75 degrees. Find the fourth angle?

tresset_1 [31]

Answer:

120 deg

Step-by-step explanation:

5 0

3 years ago

The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Bezzdna [24]

Answer:

The voltage at the middle source is $(2-4\mathbf{i})\ V$

Step-by-step explanation:

Voltage Sources in Series

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

$2 + 6\mathbf{i}$

$a + b\mathbf{i}$

$2 - 5\mathbf{i}$

The sum of these voltages is:

$V_t=4+a+(6+b-5)\mathbf{i}$

Operating:

$V_t=4+a+(1+b)\mathbf{i}$

We know the total voltage is $6-3\mathbf{i}$ , thus:

$4+a+(1+b)\mathbf{i}=6-3\mathbf{i}$

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is $(2-4\mathbf{i})\ V$

5 0

3 years ago