Answer:
There is only one solution and the solution is (0,4).
Step-by-step explanation:
The given system has equations;
and
We equate the two equations to determine their point of intersection;
We put x=0 into the first equation to get;
There is only one solution and the solution is (0,4).
5ax+2a=9a
5ax+2a-2a=9a-2a
5ax =7a
5ax/5a =7a/5a
x=7/5
V= -7/12
My steps:
-2/7v - 5/3 +5/3 = -3/2 + 5/3
-2v/7=1/6
7 x -2v/7 = 1/6 x 7
-2v = 7/6
-2v divided by -2= 7/6 divided by -2
V= -7/12
Answer: 0.3983
Step-by-step explanation:
This can be likened to having 5 samples And determining the probability of getting 1 of these 5 people getting an athlete foot.
This is Solved by using the probability distribution formula selection method for finding the probability of occurrence of a random variable. X.
When X=r, the Formula is denoted by:
P(X=r) = nCr × p^r × q^n-r
Where n=number of sample and in this case n=5
p= probability of success and in this case, p=0.16
q= probability of failure = 1-p = 1-0.16 = 0.84
r = favourable outcome from available sample = 1.
P(X=1) = 5C1 × 0.16^1 × 0.84^4
P(X=1) = 0.3983.
<h3>
Answer:</h3>
A) Shading is below the line y=2x-7, and that line is dashed. Shading is above the line y=-x/2+3, and that line is solid. The solution area is where the shading overlaps.
B) No. It fails to satisfy the second inequality.
<h3>
Step-by-step explanation:</h3>
Part A. The boundary line of the first inequality has a slope of +2 and a y-intercept of -7. Since allowed y-values are less than those on this line, the line is dashed and the shading is below the line. The solution space is shown with blue shading in the attachment.
The boundary line of the second inequality has a slope of -1/2 and a y-intercept of +3. Allowed values of y are equal to or greater than those on this line, so the line is solid and shading is above the line. The solution space is shown with green shading in the attachment.
The solution space is where the shaded areas overlap, generally to the upper right of the graph.
Part B. The point (3, -7) is in the shaded area for the first inequality, but not for the second. It does not meet the requirement for y ≥ -1/2x +3. You can see this when you substitute the point values:
-7 ≥ -1/2(3) +3 ⇒ -7 ≥ 3/2 ⇒ FALSE