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3 years ago

Heyy could you help me out with this question I have been stuck in this question??

Mathematics

1 answer:

sveta [45]3 years ago

3 0

Answer:

Choice A.

Step-by-step explanation:

tan < ABC = 60/40

So m < ABC = 56.31 degrees.

This makes m < DBC = 56.31 / 2 = 28.15 degrees

tan 28.15 = DC / 40

DC = 40 tan 28.15

= 21.407 ft.

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The perimeter p of the rectangle equals 30. Find the value of X?

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

The perimeter is calculated by multiplying the sum of width and height with 2

2*(4x-2+7x+9) = 300 solve inside the parenthesis

2*(11x+7) = 300 multiply inside the parenthesis with 2

22x + 14 = 300 subtract 14 from both sides

22x = 286 divide both sides by 22

x = 13

3 0

3 years ago

Part two out of six plz

podryga [215]

Factors of 24:
1,2,3,4,6,8,12,24

factors of 84:
1,2,3,4,6,7,12,14,21,28,42

highest common factor of 24 and 84:
12

Hope this helps!

6 0

3 years ago

Equivalent fraction of 6/126

Mice21 [21]

Answer:

1/21

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST ANSWER! ( CORRECT ANSWER )

Likurg_2 [28]

That would be 20/120 or reduced to 1/6, C.

5 0

3 years ago

Read 2 more answers

3. Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10)

Artemon [7]

<u>Answer:</u>

$y = -\frac{1}{6}x +\frac{31}{3}$

<u>Step-by-step explanation:</u>

We are to find the equation for the line which is perpendicular to another line with the equation $y = 6x - 5$ and passes through a point (2, 10).

Since the slope of a line which is perpendicular to another line is the negative reciprocal of the other line, therefore the slope of our line will be $-\frac{1}{6}$ .

Finding the y-intercept:

$y=mx+c$

$10=-\frac{1}{6} (2)+c$

$c=\frac{31}{3}$

Therefore, the equation of the line will be $y = -\frac{1}{6}x +\frac{31}{3}$ .

6 0

4 years ago

Heyy could you help me out with this question I have been stuck in this question??​

Heyy could you help me out with this question I have been stuck in this question??