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3 years ago

Heyy could you help me out with this question I have been stuck in this question??

Mathematics

1 answer:

sveta [45]3 years ago

3 0

Answer:

Choice A.

Step-by-step explanation:

tan < ABC = 60/40

So m < ABC = 56.31 degrees.

This makes m < DBC = 56.31 / 2 = 28.15 degrees

tan 28.15 = DC / 40

DC = 40 tan 28.15

= 21.407 ft.

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Round your answer to the nearest hundredth

BigorU [14]

Answer: 71.6°

tan-1(9/3) = 71.56505118°

3 0

3 years ago

Read 2 more answers

a bank receives a initial deposit of 9,000, kept a percentage of 9% and loaned out the rest. The loan was paid back. If this cyc

SSSSS [86.1K]

9000/0.09=100000 ...................

3 0

3 years ago

On a coordinate plane, a parabola opens up. It goes through (negative 7.5, 4), has a vertex of (negative 3, negative 9), and goe

morpeh [17]

Answer:

f(-3) = -9.

Step-by-step explanation:

The equation of the curve in vertex form is:

f(x) = a(x + 3)^2 - 9 a is positive as the parabola opens up.

It passes through the point (1.5, 4), so

4 = a(1.5 + 3)^2 - 9

20.25a = 13

a = 13/20.25

a = 0.6420.

So the equation of the graph is

0.6420(x + 3)^2 - 9.

f(-3) = 0.6420(-3 + 3)^2 - 9

= 0.642*0 - 9.

= -9.

7 0

3 years ago

PLSSS ANSWER!!! tnk u!!!

8090 [49]

Answer:

1.true

2.false

3.true

4.true

5.true

6.fales

7.true

8.true

9.false

10.false

Step-by-step explanation:

sana makatulog

5 0

2 years ago

A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Solution:

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

Solve the equation for "x"

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0

3 years ago

Heyy could you help me out with this question I have been stuck in this question??​

Heyy could you help me out with this question I have been stuck in this question??