Answer:

Step-by-step explanation:
![~~~~~~~2^n+2^n+2^n+2^n = 2^{16}\\\\\implies 4 \cdot 2^n = 2^{16}\\\\\implies 2^2 \cdot 2^n = 2^{16}\\\\\implies 2^{n+2} = 2^{16}~~~~~~~~~~~~~~~~~~~~~~~~~~~~;[a^m \cdot a^n = a^{m+n}]\\\\\implies n+ 2 = 16\\\\\implies n = 16-2 \\\\\implies n = 14](https://tex.z-dn.net/?f=~~~~~~~2%5En%2B2%5En%2B2%5En%2B2%5En%20%3D%202%5E%7B16%7D%5C%5C%5C%5C%5Cimplies%204%20%5Ccdot%202%5En%20%3D%202%5E%7B16%7D%5C%5C%5C%5C%5Cimplies%202%5E2%20%5Ccdot%202%5En%20%3D%202%5E%7B16%7D%5C%5C%5C%5C%5Cimplies%202%5E%7Bn%2B2%7D%20%3D%202%5E%7B16%7D~~~~~~~~~~~~~~~~~~~~~~~~~~~~%3B%5Ba%5Em%20%5Ccdot%20a%5En%20%3D%20a%5E%7Bm%2Bn%7D%5D%5C%5C%5C%5C%5Cimplies%20n%2B%202%20%3D%2016%5C%5C%5C%5C%5Cimplies%20n%20%3D%2016-2%20%5C%5C%5C%5C%5Cimplies%20n%20%3D%2014)
Answer: the answer is C
Step-by-step explanation:
just answered it and it was correct :)
we know that
Any function f(x) is continuous at x=a only if

We can see that this curve is smooth everywhere except at x=3
so, we will check continuity at x=3
Left limit is:

Right limit is:

Functional value:

we can see that left limit is not equal to right limit
so, limit does not not exist
so, this function is discontinuous at x=3
Since, limit does not exist
so, there will be non-removal discontinuity at x=3
so, option-C........Answer
Answer:
Yes
Step-by-step explanation:
A rational number is a number that can be expressed as a fraction. In this case, the fraction is being expressed by a decimal. So therefore 7.29 is a rational number.
Hope This Helps :)
Answer:
FALSE !
Step-by-step explanation: